假设以下BQ查询:
SELECT * FROM (
SELECT CONCAT(CAST(fullVisitorId AS String), CAST(visitId AS STRING)) AS CustVisitId, hits.hitnumber AS HitNr, hits.transaction.transactionRevenue/1000000 AS Rev
FROM
`[projectid].[dataset].ga_sessions_*` AS t, t.hits AS hits
WHERE
_TABLE_SUFFIX BETWEEN '20190120' AND '20190120'
ORDER BY HitNr)
WHERE CustVisitId = '49889154628941922861547956449'
这将产生一个像这样的表:
CustVisitId HitNr Rev
123456789 1
123456789 2
123456789 3
123456789 4 8
123456789 5
123456789 6
123456789 7
123456789 8
123456789 9 40
123456789 10
现在,我想添加一列(在下面的示例中为“新建”),以标识交易之前(包括交易)的所有匹配,如下所示:
CustVisitId HitNr Rev New
123456789 1 1
123456789 2 1
123456789 3 1
123456789 4 8 1
123456789 5 2
123456789 6 2
123456789 7 2
123456789 8 2
123456789 9 40 2
123456789 10 3
有人知道如何调整查询以生成所需的表吗?
答案 0 :(得分:2)
以下是用于BigQuery标准SQL
#standardSQL
SELECT *,
1 + (COUNT(Rev) OVER(PARTITION BY CustVisitId ORDER BY HitNr ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING)) `New`
FROM (
SELECT CONCAT(CAST(fullVisitorId AS STRING), CAST(visitId AS STRING)) AS CustVisitId, hits.hitnumber AS HitNr, hits.transaction.transactionRevenue/1000000 AS Rev
FROM
`[projectid].[dataset].ga_sessions_*` AS t, t.hits AS hits
WHERE
_TABLE_SUFFIX BETWEEN '20190120' AND '20190120'
ORDER BY HitNr)
WHERE CustVisitId = '49889154628941922861547956449'
如您所见,我保持查询不变,只是为New
添加了一行