Question

我需要执行以下卷曲请求：

curl -u "apikey:{apikey}" "{url}"

如何在javascript中执行此操作？特别是我在处理-u curl字段到javascript请求时遇到了一些麻烦。

Answer 1

使用JavaScript时，必须使用API密钥指定基本身份验证标头（Authorization: Basic <base64 of apikey:value>）。如果您使用的是XMLHttpRequest，请查看以下内容：https://developer.mozilla.org/en-US/docs/Web/API/XMLHttpRequest/setRequestHeader

Answer 2

您不能通过curl调用javascript。您确定要调用javascript而不发布json吗？

ex

curl -i -X POST -u user:userpass -H 'Accept: application/json' -H 'Content-type: application/json' --url 'http://myserver' -d '{
  apikey:"ddasds",
  url:"http://myserver"
}'

Answer 3

要扩展@whirlwin的答案，您可以使用以下代码生成所需的标头值：

const apiKey = "someApiKey"
const basicAuthValue = Buffer.from(`apikey:${apikey}`).toString("base64");
const authHeaderValue = `Basic ${basicAuthValue}`

//node
let requestOpts = {/* node http options */}; 
requestOpts = { 
    ...requestOpts, 
    headers: { 
        ...requestOpts.headers, 
        "Authorization": authHeaderValue 
    } 
}

//browser
const request = new XMLHttpRequest();
request.setRequestHeader("Authorization", authHeaderValue)

Answer 4

这是香草js的解决方案。

var request = new XMLHttpRequest();
request.open("GET", yourUrl, true);
request.setRequestHeader("apikey","someapikey778229"); 
request.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {
        //do something here;
    }
};
request.send();

Curl -u使用javascript请求

4 个答案: