Question

我正在尝试从员工表中获取员工等级并设置值基于等级并返回整数值，但由于返回附近的语法错误，我在第二行得到错误我正在尝试学习sql server

 create procedure checkgrade(@empid int)
    returns int
    as 
    begin
        declare @cgrade char(1)
        declare @rint int
            select @cgrade=grade from employee where @empid=empid
            if @cgrade='M' set @rint =1
            else if  @cgrade='L' set @rint=2
            else if @cgrade='T' set @rint=3
            else if @cgrade='X' set @rint= 4
            else set @rint=0
        return @rint
    end;

Answer 1

您已在过程中使用函数的语法。

create Function checkgrade(@empid int)
returns int
as 
begin
    declare @cgrade char(1)
    declare @rint int
        select @cgrade=grade from employee where @empid=empid
        if @cgrade='M' set @rint =1
        else if  @cgrade='L' set @rint=2
        else if @cgrade='T' set @rint=3
        else if @cgrade='X' set @rint= 4
        else set @rint=0

    return @rint
end;

Answer 2

您可以使用Function代替Procedure。

create Function checkgrade(@empid int)
    returns int
    as 
    begin
        declare @cgrade char(1)
        declare @rint int
            select @cgrade=grade from employee where @empid=empid
            if @cgrade='M' set @rint =1
            else if  @cgrade='L' set @rint=2
            else if @cgrade='T' set @rint=3
            else if @cgrade='X' set @rint= 4
            else set @rint=0
        return @rint
    end;

Answer 3

您可以使用output参数输出结果

create procedure checkgrade @empid int, @rint int OUTPUT   
    as 
    begin
        declare @cgrade char(1)

            select @cgrade=grade from employee where @empid=empid
            if @cgrade='M' set @rint =1
            else if  @cgrade='L' set @rint=2
            else if @cgrade='T' set @rint=3
            else if @cgrade='X' set @rint= 4
            else set @rint=0       
    end

Answer 4

CREATE PROCEDURE的语法略有不同：

 create procedure checkgrade(@empid int)
    as
    begin
        declare @cgrade char(1)
        declare @rint int
            select @cgrade=grade from employee where @empid=empid
            if @cgrade='M' set @rint =1
            else if  @cgrade='L' set @rint=2
            else if @cgrade='T' set @rint=3
            else if @cgrade='X' set @rint= 4
            else set @rint=0
        return @rint
    end;

实际上，可能是您需要功能而不是其他成员建议的过程

如何在返回值附近修复错误的语法

4 个答案: