我正在尝试在symfony 4.2.3上设置FOS Rest Bundle。并且我正在学习本教程:
https://www.thinktocode.com/2018/03/26/symfony-4-rest-api-part-1-fosrestbundle/
安装并配置了捆绑软件:
//annotations.yaml
rest_controller:
resource: ../../src/Controller/Rest/
type: annotation
prefix: /api
//fos_rest.yaml
fos_rest:
view:
view_response_listener: true
format_listener:
rules:
- { path: ^/api, prefer_extension: true, fallback_format: json, priorities: [ json ] }
,当我调用我的ArticleController对象的postAction()时:
class ArticleController extends FOSRestController
{
/**
* Creates an Article resource
* @Rest\Post("/articles")
* @param Request $request
* @return View
*/
public function postArticle(Request $request): View
{
$entityManager = $this->getDoctrine()->getManager();
$article = new Article();
$article->setTitle($request->get('title'));
$article->setContent($request->get('content'));
$articleCategory = $entityManager->getReference(ArticleCategory::class, $request->get('article_category'));
$article->setArticleCategory($articleCategory);
$article->setPublished($request->get('published'));
$entityManager->persist($article);
$entityManager->flush();
// In case our POST was a success we need to return a 201 HTTP CREATED response
return View::create($article, Response::HTTP_CREATED);
}
}
我收到错误消息(使用Postman进行测试): 控制器必须返回“ Symfony \ Component \ HttpFoundation \ Response”对象,但返回的对象类型为FOS \ RestBundle \ View \ View。
那是为什么?定义postArticle()方法应返回View对象,而我正在这样做。
一个通知:我的类正在扩展FOSRestController类,该类已被弃用。我还尝试扩展AbstractFOSRestController,但结果相同。
答案 0 :(得分:0)
因此,由于某种原因,我的fos_rest.yaml文件不在全局的包目录中,而是在包的测试子目录中。当我将它移到它的位置时,它开始工作。