Question

我再次需要您的帮助。如何在Java中对txt文件中的记录进行排序？

这是我保存分数的代码

$string ="U+FE91";
$utf8string = html_entity_decode(preg_replace("/U\+([0-9A-F]{4})/", "&#x\\1;", $string), ENT_NOQUOTES, 'UTF-8');

$query = mysqli_query($connection, "SELECT * FROM arabicwords WHERE ArWord LIKE '%".$utf8string."%' ");

这是我如何显示分数的代码

try {
    File highscore = new File("highscore.txt");
    PrintWriter output = new PrintWriter(new FileWriter(highscore, true));

    if (highscore.exists()) {
        System.out.println();
        System.out.println("High Score:");
    }

    output.println(name + " - " + totalScore);
    output.close();
} catch (IOException e) {
    System.out.println(e);
}

我当前的输出是：

try {
    FileReader fr = new FileReader("highscore.txt");
    BufferedReader br = new BufferedReader(fr);
    String s;

    while ((s = br.readLine()) != null) {
        System.out.println(s);
    }

    br.close();
} catch (IOException e) {
    System.out.println(e);
}

我想将分数从最高到最低排序，我该如何处理？预先谢谢你！

我想要得到的输出是：

Player1 100
Player2 200
Player3 50

Answer 1

根据@ luk2302和@yshavit，您需要将阅读循环更改为其他内容：

while ((s = br.readLine()) != null) {
    // 1. Create a custom object from found lines and push them into a list
}
// 2. Sort the list
// 3. Print the list

您可能也想更改保存例程，但没有要求，所以我跳过了它。

Answer 2

我建议使用Java排序功能，在这种情况下，我将创建一个包含名称和分数的对象Highscore.class。

public class Highscore {
    private String name;
    private Integer score;

    public Highscore(String name, Integer score) {
        this.name = name;
        this.score = score;
    }

    // getters...
 }

有了该对象，您必须创建List<Highscore>并对该对象进行排序...

List<Highscore> highscores = new ArrayList();
//add all highscores e.g. highscores.add(new Highscore(name, totalScore));

highscores.sort(Comparator.comparing(Highscore::getScore));

排序后，您可以将高分放入文件中。

Java：如何对txt文件进行排序？

2 个答案: