我有一个数据帧列表,我要在其中读取特定属性,然后将其所属的各个数据帧的第一行附加到该行。
在下面的数据中,我想动态读取DP.UniqueId
,可以按以下步骤进行操作,但是不确定如何将其追加为DP.UniqueId
所属的数据帧的第一行,以便获得输出如示例输出所示。
library(purrr)
new_data %>% map(pluck, 1, attr_getter("SpotfireColumnMetaData"), "DP.UniqueId")
# $A
# [1] "A-024"
# $B
# [1] "B-025"
在代码积分@MrFlick上作为对this question的回答。
这是我想动态执行的操作,因为列表中有数千个数据帧。
数据
new_data <- list(A = structure(list(AA = structure(5.49485, SpotfireColumnMetaData = list(
DP.TestNumber = "111", DP.Type = "", DP.TestName = "ABC",
DP.Info = "PTR", DP.TestUnit = "Mohm", DP.Statistic = "raw",
DP.Program = "", DP.ScaleFactor = 0L, DP.FilteredOutCells = 0L,
Limits.Prod.Lower = 2, Limits.Prod.Target = NaN, Limits.Prod.Upper = 7,
Limits.Spec.Lower = -Inf, Limits.Spec.Target = NaN, Limits.Spec.Upper = Inf,
Limits.Outlier.Lower = -Inf, Limits.Outlier.Target = NaN,
Limits.Outlier.Upper = Inf, Limits.Whatif.Lower = -Inf, Limits.Whatif.Target = NaN,
Limits.Whatif.Upper = Inf, DP.ParamType = "PARAMETRIC", DP.BlockId = "",
DP.Scratch = "", DP.ColumnId = "", Dp.BaseName = "", DP.FTR.testtxt = "",
DP.PTR.testtxt = "A -1 <> B", DP.DTR.textdat = "",
DP.MPR.pinnum = "0", DP.UniqueId = "A-024"))), class = "data.frame", row.names = c(NA,-1L)),
B = structure(list(BB = structure(0.08707662, SpotfireColumnMetaData = list(
DP.TestNumber = "112", DP.Type = "", DP.TestName = "ABC",
DP.Info = "PTR", DP.TestUnit = "Mohm", DP.Statistic = "raw",
DP.Program = "", DP.ScaleFactor = 0L, DP.FilteredOutCells = 0L,
Limits.Prod.Lower = 2, Limits.Prod.Target = NaN, Limits.Prod.Upper = 7,
Limits.Spec.Lower = -Inf, Limits.Spec.Target = NaN, Limits.Spec.Upper = Inf,
Limits.Outlier.Lower = -Inf, Limits.Outlier.Target = NaN,
Limits.Outlier.Upper = Inf, Limits.Whatif.Lower = -Inf, Limits.Whatif.Target = NaN,
Limits.Whatif.Upper = Inf, DP.ParamType = "PARAMETRIC", DP.BlockId = "",
DP.Scratch = "", DP.ColumnId = "", Dp.BaseName = "", DP.FTR.testtxt = "",
DP.PTR.testtxt = "A -1 <> B", DP.DTR.textdat = "",
DP.MPR.pinnum = "0", DP.UniqueId = "B-025"))), class = "data.frame", row.names = c(NA,-1L)))
示例输出
$A
AA
1 A-024
2 5.49485
$B
BB
1 B-025
2 0.08707662
答案 0 :(得分:1)
使用基数R我们可以做到
lapply(new_data, function(x) rbind(attr(x[[1]],"SpotfireColumnMetaData")$DP.UniqueId,x))
$A
AA
1 A-024
2 5.49485
$B
BB
1 B-025
2 0.08707662