是的,我也看到过类似的问题,但没有一个答案实际上使我找到了解决方案。我不在任何地方使用该线程,并且相同的代码可在另一个jhipster应用程序中使用,所以我很困惑为什么此lift + shift会导致Hibernate问题。
public UserDetailsContextMapper userDetailsContextMapper() {
return new UserDetailsContextMapper() {
@Override
public UserDetails mapUserFromContext(
DirContextOperations ctx, String username,
Collection<? extends GrantedAuthority> authorities) {
log.error("2 " + username + " -> " + ctx.toString());
String lowercaseLogonName = username.toLowerCase();
Optional<User> userFromDatabase = userRepository.findOneByLogin(lowercaseLogonName);
if (!userFromDatabase.isPresent()) {
User ldapUser = new User();
ldapUser.setLogin(lowercaseLogonName);
ldapUser.setPassword(RandomStringUtils.random(60)); // We use LDAP password, but the password need to be set
ldapUser.setActivated(true);
try {
Attribute attribute = ctx.getAttributes().get("mail");
ldapUser.setEmail( attribute != null && attribute.size() > 0 ? (String) attribute.get(0) : "");
attribute = ctx.getAttributes().get("givenname");
ldapUser.setFirstName(attribute != null && attribute.size() > 0 ? (String) attribute.get(0) : "");
attribute = ctx.getAttributes().get("sn");
ldapUser.setLastName(attribute != null && attribute.size() > 0 ? (String) attribute.get(0) : "");
} catch (NamingException e) {
log.warn("Couldn't get LDAP details for user: " + lowercaseLogonName);
}
Set<Authority> newUserAuthorities = new HashSet<>();
Authority authority = authorityRepository.getOne(AuthoritiesConstants.USER);
newUserAuthorities.add(authority); <-- This line in the Exception
ldapUser.setAuthorities(newUserAuthorities);
ldapUser.setLangKey("en");
userRepository.saveAndFlush(ldapUser);
}
例外:
org.hibernate.LazyInitializationException: could not initialize proxy [com.app.my.let.domain.Authority#ROLE_USER] - no Session
at org.hibernate.proxy.AbstractLazyInitializer.initialize(AbstractLazyInitializer.java:155)
at org.hibernate.proxy.AbstractLazyInitializer.getImplementation(AbstractLazyInitializer.java:268)
at org.hibernate.proxy.pojo.javassist.JavassistLazyInitializer.invoke(JavassistLazyInitializer.java:73)
at com.app.my.let.domain.Authority_$$_jvst758_1e.hashCode(Authority_$$_jvst758_1e.java)
at java.util.HashMap.hash(HashMap.java:339)
at java.util.HashMap.put(HashMap.java:612)
at java.util.HashSet.add(HashSet.java:220)
at com.app.my.let.config.SecurityConfiguration$1.mapUserFromContext(SecurityConfiguration.java:249) <-- code line above
JPA属性:
jpa:
database-platform: org.hibernate.dialect.SQLServer2012Dialect
database: SQL_SERVER
show_sql: true
format_sql: true
properties:
hibernate.id.new_generator_mappings: true
hibernate.cache.use_second_level_cache: false
hibernate.cache.use_query_cache: false
hibernate.generate_statistics: true
编辑-这解决了我的问题:
Optional<Authority> optAuthority = authorityRepository.findById(AuthoritiesConstants.USER);
Authority authority = optAuthority.get();
答案 0 :(得分:2)
此行:
Authority authority = authorityRepository.getOne(AuthoritiesConstants.USER);
仅向您提供对实体的引用。在幕后它称为EntityManager#getReference
。如此说来,这不是实体,只是对象关系映射目的的参考。引发异常,因为您试图将其投射到事务环境之外。
有几种解决方案。要获得实体,您将必须使用EntityManager#find
或在事务内完成(在方法上使用@Transactional
)。在这里,您还可以调用Hibernate.initialize(authority)
从数据库中获取实体。