创建新线程,传递参数

时间:2011-03-28 16:47:25

标签: c# multithreading

我想创建一个线程,然后将参数传递给它。但我不知道如何。

Thread siteDownloader = new Thread(new ParameterizedThreadStart(GetHTML));

这是我想作为新线程启动的功能。

static string GetHTML(string siteURL)
{
    WebClient webClient = new WebClient();

    try
    {
        string sitePrefix = siteURL.Substring(0, 7);
        if (sitePrefix != "http://")
        {
            siteURL = "http://" + siteURL;
        }
    }
    catch
    {
        siteURL = "http://" + siteURL;
    }

    try
    {
        return webClient.DownloadString(siteURL);
    }
    catch
    {
        return "404";
    }
}

4 个答案:

答案 0 :(得分:21)

我个人总是使用捕获的变量,即

int a = ...
string b = ...
ThreadStart work = delegate {
    var result = DoSomethingInteresting(a, b);
    // push result somewhere; might involve a UI
    // thread switch
};
new Thread(work).Start();

这意味着在构建期间始终检查它是否正确,与传递对象参数不同。

答案 1 :(得分:12)

引用msdn

public class Work
{
    public static void Main()
    {
        // To start a thread using a shared thread procedure, use
        // the class name and method name when you create the 
        // ParameterizedThreadStart delegate. C# infers the 
        // appropriate delegate creation syntax:
        //    new ParameterizedThreadStart(Work.DoWork)
        //
        Thread newThread = new Thread(Work.DoWork);

        // Use the overload of the Start method that has a
        // parameter of type Object. You can create an object that
        // contains several pieces of data, or you can pass any 
        // reference type or value type. The following code passes
        // the integer value 42.
        //
        newThread.Start(42);

        // To start a thread using an instance method for the thread 
        // procedure, use the instance variable and method name when 
        // you create the ParameterizedThreadStart delegate. C# infers 
        // the appropriate delegate creation syntax:
        //    new ParameterizedThreadStart(w.DoMoreWork)
        //
        Work w = new Work();
        newThread = new Thread(w.DoMoreWork);

        // Pass an object containing data for the thread.
        //
        newThread.Start("The answer.");
    }

    public static void DoWork(object data)
    {
        Console.WriteLine("Static thread procedure. Data='{0}'",
            data);
    }

    public void DoMoreWork(object data)
    {
        Console.WriteLine("Instance thread procedure. Data='{0}'",
            data);
    }
}

以便您可以看到创建一个以object作为参数的方法,并将此参数传递给Start类的Thread方法

答案 2 :(得分:3)

拉法尔的解决方案可行,但我不确定你是如何从中得到你的回报价值的。正如Martinho指出的那样,ParameterizedThreadStart需要在方法上返回void。请尝试使用BackgroundWorker。

这样称呼它。

var bw = new BackgroundWorker();
bw.DoWork += new DoWorkEventHandler(bw_DoWork);
bw.RunWorkerCompleted += new RunWorkerCompletedEventHandler(bw_RunWorkerCompleted);
bw.RunWorkerAsync(url);

这是DoWork,基本上是GetHTML的修改版本。

static void bw_DoWork(object sender, DoWorkEventArgs e)
{
    WebClient webClient = new WebClient();
    string siteURL = (string)e.Argument;

    try
    {
        string sitePrefix = siteURL.Substring(0, 7);
        if(sitePrefix != "http://")
            siteURL = "http://" + siteURL;
    }
    catch
    {
        siteURL = "http://" + siteURL;
    }

    try
    {
        e.Result = webClient.DownloadString(siteURL);
    }
    catch
    {
        e.Result = "404";
    }
}

最后,在bw_RunWorkerCompleted

中执行类似的操作
static void bw_RunWorkerCompleted(object sender, RunWorkerCompletedEventArgs e)
{
    string result;
    result = (string)e.Result;
    //do something with result
}

答案 3 :(得分:1)

你看过ParametrizedThreadStart的文档了吗?您需要一个采用对象参数并且不返回任何内容的方法。因此,您需要相应地更改方法签名:

static void GetHTML(object data)
{
    string siteUrl = (string) data; // cast argument to string
    // blah blah
}

然后你需要找出一种使用返回值的方法。