如何以点分十进制格式获取Swift 4中的IP地址

Question

我试图以点分十进制格式获取我的iOS设备的IP地址。我在Stackoverflow上找到了以下代码，该代码以一组以'：'分隔的8个字符串的形式返回IP地址。

  func getIPAddress() -> String? {
        var address: String?
        var ifaddr: UnsafeMutablePointer<ifaddrs>? = nil
        if getifaddrs(&ifaddr) == 0 {
            var ptr = ifaddr
            while ptr != nil {
                defer { ptr = ptr?.pointee.ifa_next }

            let interface = ptr?.pointee
            let addrFamily = interface?.ifa_addr.pointee.sa_family
            if addrFamily == UInt8(AF_INET) || addrFamily == UInt8(AF_INET6) {

                if let name: String = String(cString: (interface?.ifa_name)!), name == "en0" {
                    var hostname = [CChar](repeating: 0, count: Int(NI_MAXHOST))
                    getnameinfo(interface?.ifa_addr, socklen_t((interface?.ifa_addr.pointee.sa_len)!), &hostname, socklen_t(hostname.count), nil, socklen_t(0), NI_NUMERICHOST)
                    address = String(cString: hostname)
                }
            }
        }
        freeifaddrs(ifaddr)
    }
    return address
}

如何以点分十进制格式（192.168.0.1）获取Swift 4中的IP地址？