我有一个变量console.log(JSON.stringify(error))
,具有:
<span id="__w2_w6NSrFgH6_contents">Translate Question</span>
另一个变量W
具有:
[[1.]
[2.]
[3.]
[4.]
[5.]]
我一直在猜测和检查如何一起X
。 [[1. 5.1 3.5 1.4 0.2]
[1. 4.9 3. 1.4 0.2]
[1. 4.7 3.2 1.3 0.2]
[1. 4.6 3.1 1.5 0.2]
[1. 5. 3.6 1.4 0.2]
[1. 5.4 3.9 1.7 0.4]
[1. 4.6 3.4 1.4 0.3]
[1. 5. 3.4 1.5 0.2]
[1. 4.4 2.9 1.4 0.2]
[1. 4.9 3.1 1.5 0.1]
[1. 5.4 3.7 1.5 0.2]
...
[1. 5.7 2.8 4.1 1.3]]
似乎有效,但形状错误:np.dot
。
我想做的是乘以这样:
对np.dot(W.T, X.T)
中的每一行 (1, 100)
。我该怎么办?
答案 0 :(得分:3)
矩阵乘法是按列行:
std::map
所以:
X
XXXXX X .
..... * X = .
..... X .
X
答案 1 :(得分:2)
答案 2 :(得分:1)
您可以使用np.matmul
:
class ProfileEditState extends State<ProfileEdit> {
@override
Widget build(BuildContext context) {
return CupertinoTabScaffold(
tabBar: CupertinoTabBar(
onTap: (n) {
// HERE <=============================
// From here,
// if the tab icon 1 is clicked,
// I want to access the Navigator
// inside the One() Widget so I can do
// Navigator.of(One()).popUntil((x) =>false))
print("tab number is $n");
},
items: <BottomNavigationBarItem>[
BottomNavigationBarItem(
icon: Icon(CupertinoIcons.home)),
BottomNavigationBarItem(icon: Icon(CupertinoIcons.padlock_solid)),
BottomNavigationBarItem(icon: Icon(CupertinoIcons.padlock_solid)),
],
),
tabBuilder: (BuildContext context, int index) {
switch (index) {
case 0:
return One(); // returns a CupertinoTabView
break;
case 1:
return Two();
break;
case 2:
return Three();
break;
}
return null;
},
);
}
}
快速检查输出:
class ProfileEditState extends State<ProfileEdit> {
@override
Widget build(BuildContext context) {
return CupertinoTabScaffold(
tabBar: CupertinoTabBar(
onTap: (n) {
// HERE <=============================
// From here,
// if the tab icon 1 is clicked,
// I want to access the Navigator
// inside the One() Widget so I can do
// Navigator.of(One()).popUntil((x) =>false))
print("tab number is $n");
},
items: <BottomNavigationBarItem>[
BottomNavigationBarItem(
icon: Icon(CupertinoIcons.home)),
BottomNavigationBarItem(icon: Icon(CupertinoIcons.padlock_solid)),
BottomNavigationBarItem(icon: Icon(CupertinoIcons.padlock_solid)),
],
),
tabBuilder: (BuildContext context, int index) {
switch (index) {
case 0:
return One(); // returns a CupertinoTabView
break;
case 1:
return Two();
break;
case 2:
return Three();
break;
}
return null;
},
);
}
}
请注意,在这种情况下,由于两个输入均为W = np.array([[1.],[2.],[3.],[4.],[5.]])
X = np.array([[1., 5.1, 3.5, 1.4, 0.2],
[1., 4.9, 3. , 1.4, 0.2],
[1. , 4.7, 3.2, 1.3, 0.2],
[1. ,4.6, 3.1, 1.5, 0.2],
[1. ,5. , 3.6, 1.4, 0.2],
[1. ,5.4, 3.9, 1.7, 0.4]])
np.matmul(X,W)
array([[28.3],
[26.4],
[26.2],
[26.5],
[28.4],
[32.3]])
,因此它等效于1*1 + 2*5.1 + 3*3.5 + 4*1.4 + 5*0.2 = 28.3
。