Question

我从文件ID，公司名称和日期中得到了三个不同的子字符串

检索时，我需要将按日期值排序的对象存储到对象中。

我已检索并将字符串转换为我需要并存储的日期格式。而不是每次都使用sql排序再次拉动，而是尝试在插入之前存储按日期排序的排序。

class ReadingFile
{
    public static String input_path = ("C:\\Users\\RAVI\\Desktop\\Skills\\inputs");
    public static String output_path = ("C:\\Users\\RAVI\\Desktop\\Skills\\outputs");
    static BufferedReader br;
    void read(){
    SimpleDateFormat sdf = new SimpleDateFormat("hh:MM.ss");
    SimpleDateFormat parsingSdf = new SimpleDateFormat("hh:MM.ss a");
    ArrayList<Object[]> list = new ArrayList<Object[]>();
    try 
    {
    File fi = new File(input_path);
    File[] fileCount = fi.listFiles();
    for (int i = 0; i < fileCount.length; i++) 
        {
        File file = fileCount[i];
        if (file.isFile()) 
            {
            System.out.println("Total file count : " + fileCount.length);
            String fileName = file.getName();
            System.out.println("File name : " + fileName);
            String data;
            br = new BufferedReader(new FileReader(input_path + "\\"+ fileName));
            while ((data = br.readLine()) != null) 
            {
            if (data.contains(">")) 
                {
                Object[] received = new Object[3];
                String dat = data.substring(data.indexOf(" ") + 1,
                data.indexOf("-") - 1);
                // System.out.println(dat);
                Date date = sdf.parse(dat.substring(
                dat.indexOf(" "), dat.lastIndexOf(".")));
                // System.out.println(date);
                String timeFormat = parsingSdf.format(date);
                // System.out.println(timeFormat);
                received[0] = dat.substring(dat.indexOf("0"),dat.indexOf(" ") + 1)+ timeFormat;
                // System.out.println(received[0]);
                received[1] = data.substring(data.indexOf("<") + 1,data.indexOf(",") - 1);
                // System.out.println(received[1]);
                received[2] = data.substring(data.indexOf("Target"),data.lastIndexOf("."));
                //System.out.println(received[2]);
                list.add(received);
                }
            }
        }
    }

在下面添加了示例输入和相应的输出

input
(8834675) 06/01/2013 04:03.36.562 -->Successful password change for user=<U753838>, Password Target=<DOW>.
(8858218) 06/01/2013 07:18.42.312 -->Successful password change for user=<U640630>, Password Target=<DOW>.
(8893874) 06/01/2013 12:14.42.410 -->Successful password change for user=<U090521>, Password Target=<DOW>.

输出

06/01/2013 04:03.36 AM U753838 Target=<DOW>
06/01/2013 07:06.42 AM U640630 Target=<DOW>
06/01/2013 12:02.42 AM U090521 Target=<DOW>

Answer 1

请尝试一次。应该做事。

public class FileWriter {
    public static void main(String[] args) throws Exception{
        try {
            BufferedReader br = new BufferedReader(new FileReader
                    (new File("Path of sample Data")));
            List<String> list = new ArrayList<>();
            br.lines().forEach(s -> {
                System.out.println(s);
                Arrays.stream(s.split("\\)")).skip(1).forEach(s1 -> {
                    String[] strArr = s1.split("-->");
                    String p2 = s1.split("=<")[1].split(">")[0];
                    String p3 = s1.split("Password")[1].trim();
                    SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy HH:mm.ss.SSS");
                    list.add(strArr[0].trim() + " " + p2 + " " + p3);
                    Collections.sort(list, (d1, d2) -> {
                        try{
                            return sdf.parse(d1.substring(0, 21)).compareTo(sdf.parse(d2.substring(0, 21)));
                        }
                        catch (ParseException e) {
                            e.printStackTrace();
                        }
                        return 0;
                    });
                });
            });
            list.stream().forEach(System.out::println);
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

Answer 2

一种简单的方法是使用这样的ISO日期格式：

    SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
    SimpleDateFormat iso = new SimpleDateFormat("yyyy-dd-MM");
...
        BufferedReader br = new BufferedReader(new FileReader(fileName));
        while ((data = br.readLine()) != null) {
          if (data.contains(">")) {
            String[] parts = data.split(" ");
            Date date = sdf.parse(parts[1]);
            String newDate = iso.format(date);
            StringBuilder newLine = new StringBuilder(newDate);
            for (int i = 2; i < parts.length; i++) {
              newLine.append(" ").append(parts[i]);
            }
            System.out.println(newLine);
            list.add(newLine.toString());
          }
        }
        br.close();

这将导致

2013-06-01 04:03.36.562 -->Successful password change for user=<U753838>, Password Target=<DOW>.
2013-06-01 07:18.42.312 -->Successful password change for user=<U640630>, Password Target=<DOW>.
2013-06-01 12:14.42.410 -->Successful password change for user=<U090521>, Password Target=<DOW>.

可以很容易地用Collections.sort(list);

进行排序

Answer 3

import java.io.BufferedReader;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Date;

public class ReadingFile {
    public static String input_path = ("D:\\Aritra\\inputs");
    public static String output_path = ("D:\\Aritra\\outputs");
    static BufferedReader br;

    void read() {
        SimpleDateFormat sdf = new SimpleDateFormat("hh:mm.ss");
        SimpleDateFormat parsingSdf = new SimpleDateFormat("hh:mm.ss a");
        ArrayList<Object[]> list = new ArrayList<Object[]>();
        try {
            File fi = new File(input_path);
            File[] fileCount = fi.listFiles();
            for (int i = 0; i < fileCount.length; i++) {
                File file = fileCount[i];
                if (file.isFile()) {
                    System.out.println("Total file count : " + fileCount.length);
                    String fileName = file.getName();
                    System.out.println("File name : " + fileName);
                    String data;
                    br = new BufferedReader(new FileReader(input_path + "\\" + fileName));
                    while ((data = br.readLine()) != null) {
                        if (data.contains(">")) {
                            Object[] received = new Object[3];
                            String dat = data.substring(data.indexOf(" ") + 1, data.indexOf("-") - 1);
                            // System.out.println(dat);
                            Date date = sdf.parse(dat.substring(dat.indexOf(" "), dat.lastIndexOf(".")));
                            // System.out.println(date);
                            String timeFormat = parsingSdf.format(date);
                            // System.out.println(timeFormat);
                            received[0] = dat.substring(dat.indexOf("0"), dat.indexOf(" ") + 1) + timeFormat;
                            // System.out.println(received[0]);
                            received[1] = data.substring(data.indexOf("<") + 1, data.indexOf(",") - 1);
                            // System.out.println(received[1]);
                            received[2] = data.substring(data.indexOf("Target"), data.lastIndexOf("."));
                            // System.out.println(received[2]);
                            //list.add(received);
                            boolean isAdded = false;

                            if (!list.isEmpty()) {
                                Date currentEntry = new SimpleDateFormat("dd/MM/yyyy hh:mm.ss a")
                                        .parse((String) received[0]);
                                int count = 0;
                                do {
                                    Object[] loopElement =  list.get(count);
                                    Date loopElementDate = new SimpleDateFormat("dd/MM/yyyy hh:mm.ss a")
                                            .parse((String) loopElement[0]);
                                    int compareResult = currentEntry.compareTo(loopElementDate);
                                    if(compareResult<=0) {
                                        list.add(count,received);
                                        isAdded = true;
                                        break;
                                    } 
                                    count++;
                                } while (count < list.size());

                            }
                            if(!isAdded) {
                                list.add(received);
                            }       
                        }
                    }
                }
            }
        } catch (ParseException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        System.out.println("<<<<<<<<<<<<<< Result >>>>>>>>>>>>>>>>");
        for(Object[] l:list) {
            for(Object l1:l) {
                System.out.print("["+l1+"]");
            }
            System.out.println();
        }
    }
    public static void main(String[] args) {
        new ReadingFile().read();
    }
}

在存储到对象数组或包含对象数组的列表中之前，如何在Java中按日期对数据进行排序？有任何线索吗？

3 个答案: