Question

有没有人有能在vb.net中绘制等边septagon的代码？

所有方面和角度都必须相等。

由于

Answer 1

不，但是如果你想到60分钟的钟面，每8.5分钟标记一个7边形状的一点。

Answer 2

这是一个绘制指定边数的正多边形的函数：

Sub poly(ByVal center As PointF, ByVal radius As Double, ByVal nSides As Integer, ByVal g As Graphics)

Dim pts(nSides) As PointF
Dim Angle As Double = Math.PI * 2 / nSides
Dim i As Integer
Dim a As Double

a = Math.PI / 2 ' first point on top
For i = 0 To UBound(pts)
  pts(i) = center + New Point(radius * Math.Cos(a), -radius * Math.Sin(a))
  a = a + Angle
  Next i

g.DrawPolygon(Pens.DarkGreen, pts)
End Sub

要调用它，请设置要绘制的图形对象。例如，要在PictureBox1中绘制它，您可以这样调用它：

Dim g As Graphics

PictureBox1.Image = New Bitmap(PictureBox1.Width, PictureBox1.Height) ' new bitmap
g = Graphics.FromImage(PictureBox1.Image) ' assign graphics object to g
g.FillRectangle(Brushes.White, 0, 0, PictureBox1.Width, PictureBox1.Height) ' white background
' draw 7-sided polygon in the center of the picturebox
poly(New PointF(PictureBox1.Width / 2, PictureBox1.Height / 2), PictureBox1.Height / 3, 7, g)

在vb.net中绘制一个septagon

2 个答案: