Question

我有一个非常简单的FLASK Web服务器，我在heroku平台的Web dyno中运行。我也有一个非常简单的python程序，该程序在单独的dyno上运行，它会打印“ hello world”，然后退出。

我的procfile看起来像这样

web: gunicorn --bind 0.0.0.0:$PORT wsgi
test: python helloWorld.py

在heroku local上，您好，世界程序结束后，网络测功机也会被杀死：

$ heroku local

8:54:29 AM test.1 |  Hello World
[DONE] Killing all processes with signal  SIGINT
8:54:29 AM test.1 Exited Successfully
8:54:29 AM web.1  |  Traceback (most recent call last):
8:54:29 AM web.1  |    File "/anaconda3/bin/gunicorn", line 7, in <module>
8:54:29 AM web.1  |      from gunicorn.app.wsgiapp import run
8:54:29 AM web.1  |    File "/anaconda3/lib/python3.7/site-packages/gunicorn/app/wsgiapp.py", line 9, in <module>
8:54:29 AM web.1  |      from gunicorn.app.base import Application
8:54:29 AM web.1  |    File "/anaconda3/lib/python3.7/site-packages/gunicorn/app/base.py", line 11, in <module>
8:54:29 AM web.1  |      from gunicorn._compat import execfile_
8:54:29 AM web.1  |    File "/anaconda3/lib/python3.7/site-packages/gunicorn/_compat.py", line 267, in <module>
8:54:29 AM web.1  |      import inspect
8:54:29 AM web.1  |    File "/anaconda3/lib/python3.7/inspect.py", line 1087, in <module>
8:54:29 AM web.1  |      'args, varargs, varkw, defaults, kwonlyargs, kwonlydefaults, annotations')
8:54:29 AM web.1  |    File "/anaconda3/lib/python3.7/collections/__init__.py", line 397, in namedtuple
8:54:29 AM web.1  |      exec(s, namespace)
8:54:29 AM web.1  |    File "<string>", line 1, in <module>
8:54:29 AM web.1  |  KeyboardInterrupt
8:54:29 AM web.1  Exited with exit code null

如何防止这种情况？

我知道问题出在helloWorld.py退出了。如果我创建的脚本不会终止，则不会发生此问题。

print("Hello World", flush=True)
while True:
    pass

Answer 1

显然，这是工头的故意行为。参见有关Github的讨论：

领班假定所有过程都是长期存在的。如果任何进程退出，Foreman将停止所有进程。

唯一的解决方案是使HelloWorld.py长期存在。

一旦用heroku local完成，所有的测功都将停止

1 个答案: