我已经实现了一个组件(用于打字培训应用程序),该组件可以在全球范围内跟踪按键,如下所示:
class TrainerApp extends React.Component {
constructor() {
// ...
this.handlePress = this.handlePress.bind(this);
}
handlePress(event) {
const pressedKey = event.key;
const task = this.state.task;
const expectedKey = task.line[task.position];
const pressedCorrectly = pressedKey == expectedKey;
this.setState(prevState => {
const newPosition = prevState.task.position +
(pressedCorrectly ? 1 : 0);
return {
// ...prevState, not needed: https://reactjs.org/docs/state-and-lifecycle.html#state-updates-are-merged
task: {
...prevState.task,
position: newPosition,
mistakeAtCurrentPosition: !pressedCorrectly
}
}
})
}
componentDidMount() {
document.addEventListener(this.keyEventTypeToHandle,this.handlePress);
}
componentWillUnmount () {
document.removeEventListener(this.keyEventTypeToHandle,this.handlePress);
}
...
}
,我想用Jest编写一些单元测试。我最初的想法是:
describe('TrainerApp.handlePress should',() => {
test('move to the next char on correct press',() => {
const app = new TrainerApp();
app.state.task.line = 'abc';
app.state.task.position = 0;
const fakeEvent = { key: 'a' };
app.handlePress(fakeEvent);
expect(app.state.task.position).toBe(1);
});
...
});
但问题是app.handlePress
依赖于this.setState
的用法,而尚未安装组件时,该用法尚未定义。当然,我可以这样修改app
:
test('move to the next char on correct press',() => {
const app = new TrainerApp();
app.setState = jest.fn(function(handler) {
this.state = handler(this.state);
});
app.state.task.line = 'abc';
app.state.task.position = 0;
const fakeEvent = { key: 'a' };
app.handlePress(fakeEvent);
expect(app.state.task.position).toBe(1);
});
甚至是这样:
class ExplorableTrainerApp extends TrainerApp {
setState(handler) {
this.state = handler(this.state);
}
}
test('move to the next char on correct press',() => {
const app = new ExplorableTrainerApp();
app.state.task.line = 'abc';
app.state.task.position = 0;
const fakeEvent = { key: 'a' };
app.handlePress(fakeEvent);
expect(app.state.task.position).toBe(1);
});
但是这似乎是一种非常脆弱的方法(在此我依靠这样的事实:.setState
是通过函数参数调用的,而仅可以使用newState
参数来调用,因此我正在测试实现细节,而不只是行为。是否有更健壮的方法可以测试这一点?