Question

我试图在Adobe Flex中创建一个简单的HTTP URLReqest，大致是代码：

var requestSender:URLLoader = new URLLoader();
var urlRequest :URLRequest = new URLRequest("http://localhost:8888");
var msg:String = "data=blah";

urlRequest.data = msg;
urlRequest.contentType = "application/x-www-form-urlencoded";
urlRequest.method = URLRequestMethod.POST;

这会产生以下内容：

POST / HTTP/1.1
Referer: app:/PersonSearch.swf
Accept: text/xml, application/xml, application/xhtml+xml, ...
x-flash-version: 10,1,85,3
Content-Type: application/x-www-form-urlencoded
Content-Length: 102
Accept-Encoding: gzip,deflate
User-Agent: Mozilla/5.0 (Windows; U; en-US) ...
Host: 127.0.0.1:8888
Connection: Keep-Alive

data=blah

我真正想要的是：

POST / HTTP/1.1
Content-Type:application/x-www-form-urlencoded
Connection:close
Via:MDS_777
Accept:*/ *
Host:localhost:8888
Content-Length:104

data=blah

任何人都知道如何删除 Accept-Encoding 等字段，添加“Via”等字段并将连接设置为“关闭”？

另外我们如何从HTTP请求中获得响应？

由于菲尔

Answer 1

Flash Player不允许您通过ActionScript更改 Accept-Encoding 或 Via 标头。如果您尝试这样做，您将收到类似这样的消息：

错误＃2096：HTTP请求标头无法通过设置Accept-Encoding 动作脚本。

如果您使用的是URL变量，可以尝试通过以下方式简化代码：

var variables:URLVariables = new URLVariables();
variables.data = "blah"; //same as doing data=blah
variables.data2 = "blah2"; //same as doing data2=blah2

var requestSender:URLLoader = new URLLoader();
var urlRequest:URLRequest = new URLRequest("http://localhost:8888");
urlRequest.method = URLRequestMethod.POST;
urlRequest.data = variables;

要获得回复，您必须在“requestSender”上收听Event.COMPLETE：

requestSender.addEventListener(Event.COMPLETE, completeHandler); 

private function completeHandler(event:Event):void {
    // do something with requestSender.data (or URLLoader(event.target).data)
}

Adobe Flex中的HTTP URLRequest

1 个答案: