Question

我正在尝试安排要存储到数据库中的json数据，即元数据中的电话号码。有人可以帮我吗。谢谢

{
    "Body":{
        "stkCallback":{
            "MerchantRequestID":"26642-2152252-1",
            "CheckoutRequestID":"ws_CO_DMZ_240346011_09022019093008828",
            "ResultCode":0,
            "ResultDesc":"The service request is processed successfully.",
            "CallbackMetadata":{
                "Item":[
                    {"Name":"Amount","Value":10.00},
                    {"Name":"MpesaReceiptNumber","Value":"NB92QAMYN2"},
                    {"Name":"Balance"},
                    {"Name":"TransactionDate","Value":20190209093032},
                    {"Name":"PhoneNumber","Value":254723513144}
                ]
            }
        }
    }
}

我的PHP代码似乎无法正确显示在电话号码上

$PhoneNumber=$json['Body']['stkCallback']["CallbackMetadata"]['Item']['PhoneNumber'];

$sql = "UPDATE pay SET ResultCode='$ResultCode' where uniqs='$PhoneNumber'";

Answer 1

$data='{
    "Body":{
        "stkCallback":{
            "MerchantRequestID":"26642-2152252-1",
            "CheckoutRequestID":"ws_CO_DMZ_240346011_09022019093008828",
            "ResultCode":0,
            "ResultDesc":"The service request is processed successfully.",
            "CallbackMetadata":{
                "Item":[
                    {"Name":"Amount","Value":10.00},
                    {"Name":"MpesaReceiptNumber","Value":"NB92QAMYN2"},
                    {"Name":"Balance"},
                    {"Name":"TransactionDate","Value":20190209093032},
                    {"Name":"PhoneNumber","Value":254723513144}
                ]
            }
        }
    }
}';

$number=false;

/* use `json_decode` to make the data usable */
$json=json_decode( $data );

/* find the array of items */
$items=$json->Body->stkCallback->CallbackMetadata->Item;

/* loop through the array until you find the one you want. */
foreach( $items as $obj ){
    if( $obj->Name=='PhoneNumber' )$number=$obj->Value;
}
/* do something with the number... */
if( $number )echo $number;

在您将数字嵌入sql的问题中-您应该考虑使用prepared statement来避免sql注入...也许像这样

$number=false;


$json=json_decode( $data );

$items=$json->Body->stkCallback->CallbackMetadata->Item;
$code=$json->Body->stkCallback->ResultCode;

foreach( $items as $obj ){
    if( $obj->Name=='PhoneNumber' )$number=$obj->Value;
}

if( $number ){
    $sql='update `pay` set `resultcode`=? where `uniqs`=?';
    $stmt=$db->prepare($sql);
    $stmt->bind_param( 'is', $code, $number );
    $stmt->execute();
}

Answer 2

这是因为$json['Body']['stkCallback']["CallbackMetadata"]['Item']是一个充满对象的数组（带有Name和Value）。

因此，您需要遍历它并获取Name === PhoneNumber：

foreach ($json['Body']['stkCallback']["CallbackMetadata"]['Item'] as $item) {
    if ($item['Name'] === 'PhoneNumber') {
        $PhoneNumber = $item['Value'];
    }
}

让我知道它是否有效。当然，在将其保存到数据库之前，您应该检查$PhoneNumber是否真正被填充。

Answer 3

您需要先将JSON对象转换为 PHP Object 。
然后，由于您的Item是一个数组，因此需要遍历它以获得所需的字段，即PhoneNumber。

因此，以下是对它的说明-

<?php
  $jsonObj = '{
    "Body":{
        "stkCallback":{
            "MerchantRequestID":"26642-2152252-1",
            "CheckoutRequestID":"ws_CO_DMZ_240346011_09022019093008828",
            "ResultCode":0,
            "ResultDesc":"The service request is processed successfully.",
            "CallbackMetadata":{
                "Item":[
                    {"Name":"Amount","Value":10.00},
                    {"Name":"MpesaReceiptNumber","Value":"NB92QAMYN2"},
                    {"Name":"Balance"},
                    {"Name":"TransactionDate","Value":20190209093032},
                    {"Name":"PhoneNumber","Value":254723513144}
                ]
            }
        }
    }
  }';

  // json_decode your json array here
  $phpObj = json_decode($jsonObj, true);

  // get items array from the main object
  $items = $phpObj['Body']['stkCallback']['CallbackMetadata']['Item'];

  // loop over items to get desired field
  foreach($items as $obj) {
    if($obj['Name'] === 'PhoneNumber')
        $PhoneNumber = $obj['Value'];
  }
  echo $PhoneNumber;
?>

Json到php数组的安排

3 个答案: