Question

我要匹配列表中的短语。

我正在使用python匹配列表中的短语。短语可以在列表中，也可以不在列表中。

line 10, in calculate
    value_list = [value_a, value_b, value_c]
NameError: name 'value_a' is not defined

如果词组1和词组2在list1内，则返回正确或100％。目的是确保词组2和词组2逐字匹配。

相反，如果该短语不在列表内，或者仅一个短语位于列表2之内，则返回false或0％。

list1 = ['I would like to go to a party', 'I am sam', 'That is 
correct', 'I am currently living in Texas']

phrase1= 'I would like to go to a party'
phrase2= 'I am sam'

可以更改

短语，使其不仅可以与这两个短语不同。例如，可以将其更改为任何用户设置，例如“我不好”。

Answer 1

似乎您只是想检查列表中的成员身份：

list1 = ['I would like to go to a party', 'I am sam', 'That is correct', 'I am currently living in Texas']

phrase1 = 'I would like to go to a party'
phrase2 = 'I am sam'

if phrase1 in list1 and phrase2 in list1:
    # whatever you want, this will execute if True
    pass
else:
    # whatever you want, this will execute if False
    pass

Answer 2

我不确定我是否了解您，但我想也许您可以尝试

if phrase1 in list1

检查短语是否在列表中。

Answer 3

您可以使用all和一个理解：

def check(phrase_list, *phrases):
  return all(p in phrase_list for p in phrases)

使用中：

list1 = ['I would like to go to a party', 'I am sam', 'That is correct', 'I am currently living in Texas']

phrase1= 'I would like to go to a party'
phrase2= 'I am sam'

print(check(list1, phrase1, phrase2))
#True
print(check(list1, 'I am sam', 'dragon'))
#False

您也可以使用set

赞：

set(list1) >= {phrase1, phrase2}
#True

或者这样：

#you can call this the same way I called the other check
def check(phrase_list, *phrases):
  return set(list1) >= set(phrases)

修改

要打印100％或0％，您可以简单地使用if语句或使用布尔索引：

print(('0%', '100%')[check(list1, phrases)])

要在您的return语句中这样做：

return ('0%', '100%')[the_method_you_choose]

匹配列表中的短语

3 个答案: