Question

我正在使用Chosen插件创建一个select，如果找不到搜索到的option，则可以动态添加一个新的select。所说的select从mySQL表（第1列）中获取数据，并将其作为option（inc/topicselect.inc.php文件）插入到option中。

要在select内添加新的chosen.jquery.js，请在下面的select内使用JavaScript代码（案例13），该代码已与Enter键挂钩。现在，它可以完美工作，但只能将其临时插入option中，这意味着刷新后，一切都消失了。

我要实现的目标是获取新添加的<select data-placeholder="Wybierz tematy:" class="topic-dropdown" name="topic" action="inc/topicselect.inc.php" class="chosen-select" multiple> <?php require 'inc/topicselect.inc.php' ?> </select>并使用PHP（最后一个代码段）将其插入到表中，以便以后在使用时向所有用户永久显示（工作）是从早期获取的。

关于如何将JavaScript与PHP插入桥接的任何想法？

case 13:
  evt.preventDefault();
  if (this.results_showing) {
    if (!this.is_multiple || this.result_highlight) {
      return this.result_select(evt);
    }
    $(".topic-dropdown").append('<option>' + $(evt.target).val() + '</option>');
    $(".topic-dropdown").trigger('chosen:updated');
    this.result_highlight = this.search_results.find('li.active-result').lastreturn;
    this.result_select(evt);
  }
  break;

<?php if(isset($_POST["?"])) {
  require "connect.inc.php";
  $topic=$_POST["topicname"];
  if(empty($topic)) {
    header("Location: ../index.php#dodajpost?puste");
    exit();
  }
  else {
    $sql="SELECT name FROM topics WHERE name=?";
    $stmt=mysqli_stmt_init($conn);
    if(!mysqli_stmt_prepare($stmt, $sql)) {
      header("Location: ../index.php#dodajpost?error=sqlerror");
      exit();
    }
    else {
      mysqli_stmt_bind_param($stmt, "s", $_POST["topicname"]);
      mysqli_stmt_execute($stmt);
      mysqli_stmt_store_result($stmt);
      $resultcheck=mysqli_stmt_num_rows();
      if($resultcheck > 0) {
        header("Location: ../index.php#dodajpost?jużjest");
        exit();
      }
      else {
        $sql="INSERT INTO topics (name) VALUES (?)";
        $stmt=mysqli_stmt_init($conn);
        if(!mysqli_stmt_prepare($stmt, $sql)) {
          header("Location: ../index.php#dodajpost?błądzapisu");
          exit();
        }
        else {
          mysqli_stmt_bind_param($stmt, "s", $_POST["topicname"]);
          mysqli_stmt_execute($stmt);
          header("Location: ../index.php#dodajpost");
          exit();
        }
      }
    }
  }
  mysqli_stmt_close($stmt);
  mysqli_close($conn);
}

else {
  header("Location: ../index.php#dodajpost?errorstart");
  exit();
}

?>

var Income = (from u in db.OrderDetails
join p in db.Product on u.ProductId equals p.ProductId
join o in db.Orders on u.OrderId equals o.OrderId
where o.Paid == true 
group u by u.Product.Description into g
select new
{
  KindOfProduct = g.Key,
  AmountSold = g.Count(),
  TotalPrice = g.Sum(x => x.Product.Price) 
  }).ToList();
     if (Income != null)
     {
        var orderCart = new BindingSource();
        orderCart.DataSource = Income;
        dgvShoppingCart.DataSource = orderCart;
        this.dgvShoppingCart.Sort(this.dgvShoppingCart.Columns  ["AmountSold"], ListSortDirection.Ascending);

     for (int i = 0; i < dgvShoppingCart.Rows.Count; i++)
      {
        sumBar += Convert.ToDecimal(dgvShoppingCart.Rows[i].Cells["TotalPrice"].Value);
      }
     lblTotalSale.Text = sumBar.ToString();
   }

使用PHP将选择的插件中的新选项插入到MySQL中

0 个答案: