Question

我在尝试对复杂对象进行排序时遇到麻烦。这是对象结构：

[{
    "searchResultProperties": [{
        "key": "message_time",
        "value": 1542088800000
    }, {
        "key": "size_byte AVG",
        "value": 480
    }, {
        "key": "source_file",
        "value": "log"
    }, {
        "key": "source_host",
        "value": "lab8.domain.com"
    }],
    "show": false,
    "key": null,
    "type": null
}, {
    "searchResultProperties": [{
        "key": "message_time",
        "value": 1542096000000
    }, {
        "key": "size_byte AVG",
        "value": 373
    }, {
        "key": "source_file",
        "value": "log"
    }, {
        "key": "source_host",
        "value": "lab8.domain.com"
    }],
    "show": false,
    "key": null,
    "type": null
}, {
    "searchResultProperties": [{
        "key": "message_time",
        "value": 1542103200000
    }, {
        "key": "size_byte AVG",
        "value": 683
    }, {
        "key": "source_file",
        "value": "log"
    }, {
        "key": "source_host",
        "value": "lab8.domain.com"
    }],
    "show": false,
    "key": null,
    "type": null
}]

基本上，它是具有称为“ searchResultProperties”的属性的对象的数组，该属性是具有“键”和“值”属性的对象的数组。

我正在尝试对“键”属性进行排序，即：“ size_byte AVG”。

Answer 1

您可以使用Array.prototype.sort()函数，该函数为您提供两个对象，并且可以根据排序逻辑返回+ ve或-ve值。请参阅[https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort]

array = [{
    "searchResultProperties": [{
        "key": "message_time",
        "value": 1542088800000
    }, {
        "key": "size_byte AVG",
        "value": 480
    }, {
        "key": "source_file",
        "value": "log"
    }, {
        "key": "source_host",
        "value": "lab8.domain.com"
    }],
    "show": false,
    "key": null,
    "type": null
}, {
    "searchResultProperties": [{
        "key": "message_time",
        "value": 1542096000000
    }, {
        "key": "size_byte AVG",
        "value": 373
    }, {
        "key": "source_file",
        "value": "log"
    }, {
        "key": "source_host",
        "value": "lab8.domain.com"
    }],
    "show": false,
    "key": null,
    "type": null
}, {
    "searchResultProperties": [{
        "key": "message_time",
        "value": 1542103200000
    }, {
        "key": "size_byte AVG",
        "value": 683
    }, {
        "key": "source_file",
        "value": "log"
    }, {
        "key": "source_host",
        "value": "lab8.domain.com"
    }],
    "show": false,
    "key": null,
    "type": null
}]

array = array.sort((a,b) => a.searchResultProperties.find(obj => obj.key === "size_byte AVG").value - b.searchResultProperties.find(obj => obj.key === "size_byte AVG").value )

console.log(array);

Answer 2

您可以使用函数find来查找键为size_byte AVG的对象，并使用函数sort来对数组进行排序。

此方法按升序排序

let arr = [{    "searchResultProperties": [{        "key": "message_time",        "value": 1542088800000    }, {        "key": "size_byte AVG",        "value": 480    }, {        "key": "source_file",        "value": "log"    }, {        "key": "source_host",        "value": "lab8.domain.com"    }],    "show": false,    "key": null,    "type": null}, {    "searchResultProperties": [{        "key": "message_time",        "value": 1542096000000    }, {        "key": "size_byte AVG",        "value": 373    }, {        "key": "source_file",        "value": "log"    }, {        "key": "source_host",        "value": "lab8.domain.com"    }],    "show": false,    "key": null,    "type": null}, {    "searchResultProperties": [{        "key": "message_time",        "value": 1542103200000    }, {        "key": "size_byte AVG",        "value": 683    }, {        "key": "source_file",        "value": "log"    }, {        "key": "source_host",        "value": "lab8.domain.com"    }],    "show": false,    "key": null,    "type": null}],
    target = "size_byte AVG",
    compare = (a, b) => a.find(({key}) => key === target).value - b.find(({key}) => key === target).value,
    sorted = arr.sort(({searchResultProperties: a}, {searchResultProperties: b}) => compare(a, b));

console.log(sorted);

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Answer 3

您可以使用sort和find

sort接受两个值作为参数。通过find我们找到具有键'size_byte AVG'的数组元素，并从中取出值并比较值

let arr = [{"searchResultProperties": [{"key": "message_time","value": 1542088800000}, {"key": "size_byte AVG","value": 480}, {"key": "source_file",       "value": "log"}, {"key": "source_host","value": "lab8.domain.com"}],"show": false,"key": null, "type": null}, { "searchResultProperties": [{"key": "message_time","value": 1542096000000}, {"key": "size_byte AVG","value": 373}, {"key": "source_file","value": "log"}, {"key": "source_host","value": "lab8.domain.com"}],"show": false,"key": null, "type": null}, {"searchResultProperties": [{"key": "message_time","value": 1542103200000}, {"key": "size_byte AVG","value": 683 }, { "key": "source_file","value": "log"}, {"key": "source_host","value": "lab8.domain.com"}],"show": false,"key": null,"type": null}]

let op = arr.sort((a,b)=>
         a.searchResultProperties.find(e=>e.key==='size_byte AVG').value -
         b.searchResultProperties.find(e=>e.key==='size_byte AVG').value)

console.log(op)

如何通过嵌套值对复杂对象进行排序

3 个答案: