我一直在尝试模拟Pygame代码中的跳转,但未能成功实现它。有一个尺寸为10 x 10的矩形,当我按下 SPACE KEYBAR 时,我希望该矩形跳转。我暂时保持此代码不受重力的影响。
import pygame
pygame.init()
ScreenLenX = 1000
ScreenLenY = 500
win = pygame.display.set_mode((ScreenLenX, ScreenLenY))
pygame.display.set_caption("aman")
run = True
Xcord = 100
Ycord = 100
length = 10
height = 10
vel = 2
xmove = 1
ymove = 1
while run:
#pygame.time.delay(1)
for event in pygame.event.get():
print(event)
if event.type ==pygame.QUIT:
run = False
if keys[pygame.K_RIGHT] and Xcord <= ScreenLenX-length:
Xcord += vel
if keys[pygame.K_LEFT] and Xcord >= 0:
Xcord -= vel
if keys[pygame.K_UP] and Ycord >= 0:
Ycord -= vel
if keys[pygame.K_DOWN] and Ycord <= ScreenLenY - height:
Ycord += vel
win.fill((0, 0, 0))
pygame.draw.rect(win, (255, 0, 0), (Xcord, Ycord, length, height))
keys = pygame.key.get_pressed()
pygame.display.update()
pygame.quit()
答案 0 :(得分:2)
在主循环之前添加变量jump
并将其初始化为0:
jump = 0
while run:
# [...]
如果允许玩家跳跃并停留在地面上,则仅对pygame.K_SPACE
做出反应。如果满足要求,则将jump
设置为所需的“跳跃”高度:
if keys[pygame.K_SPACE] and Ycord == ScreenLenY - height:
jump = 300
在主循环中,只要jump
大于0,请向上移动玩家并降低jump
的数量。
如果玩家没有跳来跳去,直到他到达地面:
if jump > 0:
Ycord -= vel
jump -= vel
elif Ycord < ScreenLenY - height:
Ycord += 1
请参阅演示,在该示例中我将建议应用于您的代码:
import pygame
pygame.init()
ScreenLenX, ScreenLenY = (1000, 500)
win = pygame.display.set_mode((ScreenLenX, ScreenLenY))
pygame.display.set_caption("aman")
Xcord, Ycord = (100, 100)
length, height = (10, 10)
xmove, ymove = (1, 1)
vel = 2
jump = 0
run = True
clock = pygame.time.Clock()
while run:
#clock.tick(60)
for event in pygame.event.get():
print(event)
if event.type ==pygame.QUIT:
run = False
keys = pygame.key.get_pressed()
if keys[pygame.K_RIGHT] and Xcord <= ScreenLenX-length:
Xcord += vel
if keys[pygame.K_LEFT] and Xcord >= 0:
Xcord -= vel
if keys[pygame.K_SPACE] and Ycord == ScreenLenY - height:
jump = 300
if jump > 0:
Ycord -= vel
jump -= vel
elif Ycord < ScreenLenY - height:
Ycord += 1
win.fill((0, 0, 0))
pygame.draw.rect(win, (255, 0, 0), (Xcord, Ycord, length, height))
pygame.display.update()