Question

我需要做什么来使我的代码一直运行？它在我添加列的ALTER TABLE部分中断了，因为它说它们还不存在-我是否必须在此处的代码中添加某种中断？我是新手用户，但可能是因为执行每个步骤的顺序？

其中一段代码中断的示例-当前，仅当我运行所有更新（此处显示的更新超过此内容），然后再单独运行Alter Table部分时，它才有效。

update TABLE_2
set MEASURE = '-9'
where RESPONSE = '1' 
and QUESTION = '22d' and MEASURE not in (1,2)

update TABLE_2
set MEASURE = '-9'
where RESPONSE = '1' 
and QUESTION = '22e' and MEASURE not in (1,2)

update TABLE_2
set MEASURE = '-9'
where RESPONSE = '1' 
and QUESTION = '22f' and MEASURE not in (1,2)



--Create a ‘CONC’ column of La Code, Stratum and Question:

alter table TABLE_2
add [CONC] nvarchar(10)

update TABLE_2
set [CONC] = [LA_CODE] + [STRATUM_1] + [question]
where [CONC] is NULL

Answer 1

答案是go，如评论中所述。我想指出的是，前三个语句可以简化为：

update TABLE_2
    set MEASURE = -9
where RESPONSE = 1 and
      QUESTION in ('22d', '22e', '22f')
      MEASURE not in (1, 2);

然后使用go。

以这种方式组合逻辑可以使代码更具可维护性，并且不易出错。假设RESPONSE和MEAUSRE的常数是某种数字，我删除了它们的单引号。如果不是，则对所有比较和分配使用单引号。

如何使我的代码一直运行？

1 个答案: