Question

我将如何更改此代码，以使其在给定帖子的一半段落之后插入自定义内容？如果帖子包含12个段落，则内容应在数字6之后插入。如果帖子具有100，则应在数字50之后插入内容。

我在网上找到了此代码，您可以在其中指定段落的硬编码数量：

<?php
//Insert ads after second paragraph of single post content.
add_filter( 'the_content', 'prefix_insert_post_ads' );
function prefix_insert_post_ads( $content ) {
 $ad_code = '<div>Ads code goes here</div>';
 if ( is_single() && ! is_admin() ) {
 return prefix_insert_after_paragraph( $ad_code, 2, $content );
 }
return $content;
}

// Parent Function that makes the magic happen
function prefix_insert_after_paragraph( $insertion, $paragraph_id, $content ) {
 $closing_p = '</p>';
 $paragraphs = explode( $closing_p, $content );
 foreach ($paragraphs as $index => $paragraph) {
 if ( trim( $paragraph ) ) {
 $paragraphs[$index] .= $closing_p;
 }
 if ( $paragraph_id == $index + 1 ) {
 $paragraphs[$index] .= $insertion;
 }
 }

 return implode( '', $paragraphs );
}

我不知道足够的PHP使它动态。我没有在其他地方找到对此的动态答案。

Answer 1

我这样解决了：

//Insert ads after half of the paragraphs in a post
add_filter( 'the_content', 'prefix_insert_post_ads' );
function prefix_insert_post_ads( $content ) {
 $ad_code = '<div>CODE HERE</div>';
 if ( is_single() && ! is_admin() && in_category('29') ) {
 return prefix_insert_after_paragraph( $ad_code, $content );
 }
return $content;
}

// Parent Function that makes the magic happen
function prefix_insert_after_paragraph( $insertion, $content ) {
 $closing_p = '</p>';
 $paragraphs = explode( $closing_p, $content );
 $paragraph_id = round(count($paragraphs) / 2);
 foreach ($paragraphs as $index => $paragraph) {
 if ( trim( $paragraph ) ) {
 $paragraphs[$index] .= $closing_p;
 }
 if ( $paragraph_id == $index + 1 ) {
 $paragraphs[$index] .= $insertion;
 }
 }
 return implode( '', $paragraphs );
}

在这里，我还添加了类别检查。

在Wordpress帖子中间添加自定义内容

1 个答案: