播放json 2.7.1:java.lang.NoSuchMethodError

时间:2019-02-08 12:59:18

标签: scala playframework play-json

将play-json升级到2.7.0后,我开始遇到运行时错误:

[info] com.mycompany.controllers.HealthControllerSpec *** ABORTED ***
[info]   java.lang.NoSuchMethodError: play.api.libs.json.JsonConfiguration$.apply$default$2()Lplay/api/libs/json/OptionHandlers;
[info]   at com.mycompany.util.json.SnakeCase.$init$(SnakeCase.scala:41)
[info]   at com.mycompany.util.playframework.controllers.HealthView$.<init>(HealthView.scala:15)
[info]   at com.mycompany.util.playframework.controllers.HealthView$.<clinit>(HealthView.scala)
[info]   at com.mycompany.util.playframework.controllers.HealthController.<init>(HealthController.scala:25)
[info]   at com.mycompany.util.playframework.controllers.HealthControllerSpec.$anonfun$new$2(HealthControllerSpec.scala:30)
[info]   at org.scalatest.OutcomeOf.outcomeOf(OutcomeOf.scala:85)
[info]   at org.scalatest.OutcomeOf.outcomeOf$(OutcomeOf.scala:83)
[info]   at org.scalatest.OutcomeOf$.outcomeOf(OutcomeOf.scala:104)
[info]   at org.scalatest.Transformer.apply(Transformer.scala:22)
[info]   at org.scalatest.Transformer.apply(Transformer.scala:20)

有人可以指出我的理由吗?

HealthView

case class HealthView(app: String, description: String, version: Option[String])

object HealthView extends SnakeCase {

  def apply(config: Configuration): HealthView =
    HealthView(
      config.get[String]("app.name"),
      config.get[String]("app.description"),
      config.getOptional[String]("app.version")
    )

  implicit val format: OFormat[HealthView] = Json.format[HealthView]

}

SnakeCase

trait SnakeCase {

  implicit val jsonConfig: Aux[Json.MacroOptions] = JsonConfiguration(SnakeCaseNaming)

}

发行版的次要版本应与二进制兼容。

1 个答案:

答案 0 :(得分:3)

Travis Brown指出您存在版本冲突。

由于Play项目中包含play-json,因此您不应再依赖于play-json

如果有(因为我有一个多模块项目),请确保主要版本合适。

例如在plugins.sbt中:

addSbtPlugin("com.typesafe.play" % "sbt-plugin" % "2.7.0")

并作为依赖项(不在play模块中!):

"com.typesafe.play" %% "play-json" % "2.7.1"