我有两个桌子
Table A（约200万行）
ID Str
123 1=A&3=B&8=B&11=A&12=R&17=BX&19=Z&20=B&21=AK&22=AH&24=A&27=A&28=A&29=C&31=A&32=S&33=N&34=H&35=Z&37=A&38=Z&39=A&41=D&42=G&49=A&52=Z&53=C&54=D&55=Z&56=Z&57=Z&58=A&61=B&63=B&65=A&66=A&67=A&68=A&69=A&71=G&73=Q&74=AB&76=B&77=Z&79=F&80=B&82=D&83=B&89=BA&91=Z&92=Z&93=Z&95=R&97=B&98=Z&99=G&100=G&101=B&106=C&109=Z&110=A&111=Z&112=C&116=B&118=Z&120=B&121=A&122=A&124=E&125=Z&128=A&131=Z&137=F&141=A&142=B&143=Z&144=B&146=C&148=Z&153=A&157=A&164=A&167=Z&168=Z&170=C&188=E&200=A&203=B&227=Z&235=C&237=B&238=G&258=Z&259=Z&268=Z&272=B&274=D&284=B&285=C&288=A&289=Z&290=A&299=M&300=D&313=Z&315=Z&322=A&324=Z&327=Z&358=E&360=B&365=A&366=A&375=B&376=B&379=Z&381=Z&383=M&387=Z&390=Z&391=Z&392=B&393=Z&398=MA&400=Z&403=B&404=A&407=B&408=BT&410=B&412=A&413=F&414=B&415=F&416=B&419=Z&421=Z&430=C&433=Z&435=C&440=Z&441=PG&448=A&453=A&458=B&459=Z&460=Z&463=A&466=Z&468=Z&472=Z&474=A&475=Z&492=Z&496=Z&498=A&504=A&506=B&507=Z&514=D&518=B&519=Z&523=C&536=A&554=Z&557=Z&560=A&582=Z&584=A&586=Z&587=Z&588=B&591=C&599=A&603=Z&610=Z&614=B&625=A&664=A&666=C&668=C&670=Z&672=L&674=L&698=B&699=A&720=BB&745=Z&754=A&756=Z&759=Z&762=Z&766=AA&767=AA&769=A&772=HB&785=B&787=Z&788=Z&789=Z&790=Z&791=Z&792=Z&794=Z&795=A&796=Z&803=A&808=Z&809=DC&812=G&813=G&815=G&821=K&822=M&824=ES&828=Z&829=GA&831=SN&837=BC&841=K&845=K&851=S&852=Z&853=B&854=WU&855=B&856=WU&857=A&859=A&861=B&863=C&865=A&867=B&869=Z&873=ZA&882=CM&889=CD&921=Z&922=Z&924=Z&925=Z&932=B&933=Z&941=Z&952=RJ&954=Z&967=P&984=A&985=H&1002=D&1007=F&1041=F&1052=BR&1053=BR&1056=PD&1057=NA&1095=H&1104=B&1121=A&1122=M&1123=D&1162=G&1163=A&1164=B&1165=A&1166=E&1174=A&1182=A&1183=A&1185=C&1188=Z&1202=KG&1211=A&1223=B&1229=Z&1231=A&1233=Z&1237=L&1256=TW&1258=C&1259=BH&1260=D&1261=A&1272=C&1296=Z&1298=Z&1299=A&1302=A&1303=A&1308=C&1309=J&1313=A&1316=B&1317=Z&1318=A&1319=Z&1323=D&1327=A&1328=A&1329=Z&1330=Z&1331=A&1332=Z&1333=Z&1335=DS&1339=Z&1345=AE&1346=AG&1352=Z&1356=Z&1366=Z&1367=B&1368=B&1369=A&1370=W&1371=A&1373=Z&1379=GQ&1381=A&1387=CX&1388=Z&1389=EU&1391=E&1392=J&1397=Z&1399=Z&1401=Z&1405=A&1406=CN&1412=Z&1416=Z&1417=B&1419=Z&1421=Z&1424=Z&1428=Z&1431=B&1432=B&1436=A&1437=Z&1441=CB&1442=A&1443=Z&1449=A&1452=Z&1453=Z&1470=A&1473=Z&1474=A&1475=Z&1477=D&1478=B&1479=B&1481=A&1488=A&1490=D&1493=E&1494=Z&1502=Y&1503=BH&1504=C&1505=B&1506=Z&1511=Z&1512=A&1513=KU&1518=A&1524=Z&1541=A&1549=A&1554=A&1623=A&1629=Z&1637=B&1640=Z&1642=Z&1643=Z&1644=B&1661=A&1673=K&1681=A&1771=A&1772=Z&1787=Z&1788=Z&1790=Z&1793=Z&1837=A&1838=Z&1839=Z&1854=Z&1855=Z&1856=Z&1858=Z&1867=B&1872=B&1873=B&1879=Z&1881=B&1902=Z&1910=Z&1916=B&1917=A&1918=B&1920=A&1927=A&1928=Z&1963=Z&1964=Z&1968=A&1974=A&1975=Z&1976=Z&1993=Z&2007=A&2010=Z&2011=A&2012=Z&2015=Z&2022=Z&2023=Z&2024=Z&2032=Z&2037=Z&MPC-9002=AA&MPC-9006=AG&
165 1=A&2=R&4=B&33=G&34=Q&46=Y&49=A&75=AH&589=C&590=A&803=IG&812=RB&813=RB&814=RB&815=RB&841=V&843=V&844=V&845=V&851=S&853=B&854=KJ&855=B&856=KJ&857=B&858=KJ&859=B&860=KJ&861=B&862=RB&863=B&864=RB&865=B&866=RB&867=B&881=AC&883=GE&889=M&897=IS&922=C&965=CP&1323=C&
Table B（约50000行）
ID Str
1 1=A&1323=D!1=B&1323=D!1=A&1323=E!1=F&1323=D!1=B&1323=E!1=F&1323=E
2 1=B&142=D&1323=D&1470=B
3 1=A&1323=E&1470=C
我正在使用的查询是这个
SELECT A.ID, B.ID
FROM TableA AS A
CROSS APPLY TableB AS B
WHERE function(A.Str,B.Str) = 1
该函数的代码用C＃编写：
public static SqlByte function(SqlString equip, SqlString comp)
{
SqlByte result = 1;
if (comp.IsNull)
{
result = 1;
}
else
{
var eq = new List<string>(equip.ToString().Split('&'));
var compString = new List<string>(comp.ToString().Split('!'));
foreach (string com in compString)
{
foreach (string c in com.Split('&'))
{
if (c.StartsWith("~"))
{
if (eq.Contains(c.Substring(1)))
{
result = 0;
break;
}
}
else if (!eq.Contains(c))
{
result = 0;
break;
}
else
{
result = 1;
continue;
}
}
if (result == 1)
{
break;
}
}
}
return result;
}
使用给定的数据量，我大约需要6天来运行查询。我有什么办法可以加快速度吗？
非常感谢！
答案 0 :(得分：3)
正如您在使用SQL Server 2017一样，我建议使用JSON方法。一个很大的好处是OPENJSON将返回片段的位置，从而可以重新连接该片段-如果需要的话：
DECLARE @tblA TABLE(ID INT,YourString VARCHAR(MAX));
INSERT INTO @tblA VALUES
(123,'1=A&3=B&8=B&11=A&12=R&17=BX&19=Z&20=B&21=AK&22=AH&24=A&27=A&28=A&29=C&31=A&32=S&33=N&34=H&35=Z&37=A&38=Z&39=A&41=D&42=G&49=A&52=Z&53=C&54=D&55=Z&56=Z&57=Z&58=A&61=B&63=B&65=A&66=A&67=A&68=A&69=A&71=G&73=Q&74=AB&76=B&77=Z&79=F&80=B&82=D&83=B&89=BA&91=Z&92=Z&93=Z&95=R&97=B&98=Z&99=G&100=G&101=B&106=C&109=Z&110=A&111=Z&112=C&116=B&118=Z&120=B&121=A&122=A&124=E&125=Z&128=A&131=Z&137=F&141=A&142=B&143=Z&144=B&146=C&148=Z&153=A&157=A&164=A&167=Z&168=Z&170=C&188=E&200=A&203=B&227=Z&235=C&237=B&238=G&258=Z&259=Z&268=Z&272=B&274=D&284=B&285=C&288=A&289=Z&290=A&299=M&300=D&313=Z&315=Z&322=A&324=Z&327=Z&358=E&360=B&365=A&366=A&375=B&376=B&379=Z&381=Z&383=M&387=Z&390=Z&391=Z&392=B&393=Z&398=MA&400=Z&403=B&404=A&407=B&408=BT&410=B&412=A&413=F&414=B&415=F&416=B&419=Z&421=Z&430=C&433=Z&435=C&440=Z&441=PG&448=A&453=A&458=B&459=Z&460=Z&463=A&466=Z&468=Z&472=Z&474=A&475=Z&492=Z&496=Z&498=A&504=A&506=B&507=Z&514=D&518=B&519=Z&523=C&536=A&554=Z&557=Z&560=A&582=Z&584=A&586=Z&587=Z&588=B&591=C&599=A&603=Z&610=Z&614=B&625=A&664=A&666=C&668=C&670=Z&672=L&674=L&698=B&699=A&720=BB&745=Z&754=A&756=Z&759=Z&762=Z&766=AA&767=AA&769=A&772=HB&785=B&787=Z&788=Z&789=Z&790=Z&791=Z&792=Z&794=Z&795=A&796=Z&803=A&808=Z&809=DC&812=G&813=G&815=G&821=K&822=M&824=ES&828=Z&829=GA&831=SN&837=BC&841=K&845=K&851=S&852=Z&853=B&854=WU&855=B&856=WU&857=A&859=A&861=B&863=C&865=A&867=B&869=Z&873=ZA&882=CM&889=CD&921=Z&922=Z&924=Z&925=Z&932=B&933=Z&941=Z&952=RJ&954=Z&967=P&984=A&985=H&1002=D&1007=F&1041=F&1052=BR&1053=BR&1056=PD&1057=NA&1095=H&1104=B&1121=A&1122=M&1123=D&1162=G&1163=A&1164=B&1165=A&1166=E&1174=A&1182=A&1183=A&1185=C&1188=Z&1202=KG&1211=A&1223=B&1229=Z&1231=A&1233=Z&1237=L&1256=TW&1258=C&1259=BH&1260=D&1261=A&1272=C&1296=Z&1298=Z&1299=A&1302=A&1303=A&1308=C&1309=J&1313=A&1316=B&1317=Z&1318=A&1319=Z&1323=D&1327=A&1328=A&1329=Z&1330=Z&1331=A&1332=Z&1333=Z&1335=DS&1339=Z&1345=AE&1346=AG&1352=Z&1356=Z&1366=Z&1367=B&1368=B&1369=A&1370=W&1371=A&1373=Z&1379=GQ&1381=A&1387=CX&1388=Z&1389=EU&1391=E&1392=J&1397=Z&1399=Z&1401=Z&1405=A&1406=CN&1412=Z&1416=Z&1417=B&1419=Z&1421=Z&1424=Z&1428=Z&1431=B&1432=B&1436=A&1437=Z&1441=CB&1442=A&1443=Z&1449=A&1452=Z&1453=Z&1470=A&1473=Z&1474=A&1475=Z&1477=D&1478=B&1479=B&1481=A&1488=A&1490=D&1493=E&1494=Z&1502=Y&1503=BH&1504=C&1505=B&1506=Z&1511=Z&1512=A&1513=KU&1518=A&1524=Z&1541=A&1549=A&1554=A&1623=A&1629=Z&1637=B&1640=Z&1642=Z&1643=Z&1644=B&1661=A&1673=K&1681=A&1771=A&1772=Z&1787=Z&1788=Z&1790=Z&1793=Z&1837=A&1838=Z&1839=Z&1854=Z&1855=Z&1856=Z&1858=Z&1867=B&1872=B&1873=B&1879=Z&1881=B&1902=Z&1910=Z&1916=B&1917=A&1918=B&1920=A&1927=A&1928=Z&1963=Z&1964=Z&1968=A&1974=A&1975=Z&1976=Z&1993=Z&2007=A&2010=Z&2011=A&2012=Z&2015=Z&2022=Z&2023=Z&2024=Z&2032=Z&2037=Z&MPC-9002=AA&MPC-9006=AG&')
,(165,'1=A&2=R&4=B&33=G&34=Q&46=Y&49=A&75=AH&589=C&590=A&803=IG&812=RB&813=RB&814=RB&815=RB&841=V&843=V&844=V&845=V&851=S&853=B&854=KJ&855=B&856=KJ&857=B&858=KJ&859=B&860=KJ&861=B&862=RB&863=B&864=RB&865=B&866=RB&867=B&881=AC&883=GE&889=M&897=IS&922=C&965=CP&1323=C&');
-您可以通过将其转换为JSON数组轻松地拆分数据
-像1=A&3=B&8=B&11=A&12=R这样的值将是["1=A","3=B","8=B","11=A","12=R"]
SELECT ID
,A.[key] AS OrdPosition
,A.[value] AS Fragment
FROM @tblA
CROSS APPLY OPENJSON('["' + REPLACE(YourString,'&','","') + '"]') A
-您的第二张桌子是折叠的。我们也可以将其拆分为一个查询
DECLARE @tblB TABLE(ID INT,YourString VARCHAR(MAX));
INSERT INTO @tblB VALUES
(1,'1=A&1323=D!1=B&1323=D!1=A&1323=E!1=F&1323=D!1=B&1323=E!1=F&1323=E')
,(2,'1=B&142=D&1323=D&1470=B')
,(3,'1=A&1323=E&1470=C');
SELECT ID
,A.[key] AS OrdPositionA
,B.[key] AS OrdPositionB
,B.[value] AS Fragment
FROM @tblB
CROSS APPLY OPENJSON('["' + REPLACE(YourString,'!','","') + '"]') A
CROSS APPLY OPENJSON('["' + REPLACE(A.[value],'&','","') + '"]') B
将这种方法与简单的联接结合起来应该很容易。
OPENJSON的表现不错。在this answer中，我比较了STRING_SPLIT，OPENJSON和众所周知的delimited8k()函数。值得一看...
使用类似上面的查询来存储您的数据片段。无论何时需要，都可以使用STRING_AGG()取回长字符串，但繁重的工作是拆分。一次又一次地执行此操作不是很聪明...
将此用于@tlbA
SELECT ID
,A.[key] AS OrdPosition
,A.[value] AS Fragment
,x.value('/x[1]','varchar(10)') AS FragmentNumber
,x.value('/x[2]','varchar(10)') AS FragmentCharacter
FROM @tblA
CROSS APPLY OPENJSON('["' + REPLACE(YourString,'&','","') + '"]') A
CROSS APPLY(SELECT CAST('<x>' + REPLACE(A.[value],'=','</x><x>') + '</x>' AS XML)) B(x)
ORDER BY ID,OrdPosition
这是@tblB
SELECT ID
,A.[key] AS OrdPositionA
,B.[key] AS OrdPositionB
,B.[value] AS Fragment
,x.value('/x[1]','varchar(10)') AS FragmentNumber
,x.value('/x[2]','varchar(10)') AS FragmentCharacter
FROM @tblB
CROSS APPLY OPENJSON('["' + REPLACE(YourString,'!','","') + '"]') A
CROSS APPLY OPENJSON('["' + REPLACE(A.[value],'&','","') + '"]') B
CROSS APPLY(SELECT CAST('<x>' + REPLACE(B.[value],'=','</x><x>') + '</x>' AS XML)) C(x)
ORDER BY ID,OrdPositionA,OrdPositionB
这将返回每个值整齐分开的值。将其填充到物理表中，放置索引并享受返回的速度。
存储这些表中的值，并通过简单的STRING_AGG()查询返回原始的大字符串...
回答您的评论，这是加入这些结果的一种简单方法：
DECLARE @tblA TABLE(ID INT,YourString VARCHAR(MAX));
INSERT INTO @tblA VALUES
(123,'1=A&3=B&8=B&11=A&12=R&17=BX&19=Z&20=B&21=AK&22=AH&24=A&27=A&28=A&29=C&31=A&32=S&33=N&34=H&35=Z&37=A&38=Z&39=A&41=D&42=G&49=A&52=Z&53=C&54=D&55=Z&56=Z&57=Z&58=A&61=B&63=B&65=A&66=A&67=A&68=A&69=A&71=G&73=Q&74=AB&76=B&77=Z&79=F&80=B&82=D&83=B&89=BA&91=Z&92=Z&93=Z&95=R&97=B&98=Z&99=G&100=G&101=B&106=C&109=Z&110=A&111=Z&112=C&116=B&118=Z&120=B&121=A&122=A&124=E&125=Z&128=A&131=Z&137=F&141=A&142=B&143=Z&144=B&146=C&148=Z&153=A&157=A&164=A&167=Z&168=Z&170=C&188=E&200=A&203=B&227=Z&235=C&237=B&238=G&258=Z&259=Z&268=Z&272=B&274=D&284=B&285=C&288=A&289=Z&290=A&299=M&300=D&313=Z&315=Z&322=A&324=Z&327=Z&358=E&360=B&365=A&366=A&375=B&376=B&379=Z&381=Z&383=M&387=Z&390=Z&391=Z&392=B&393=Z&398=MA&400=Z&403=B&404=A&407=B&408=BT&410=B&412=A&413=F&414=B&415=F&416=B&419=Z&421=Z&430=C&433=Z&435=C&440=Z&441=PG&448=A&453=A&458=B&459=Z&460=Z&463=A&466=Z&468=Z&472=Z&474=A&475=Z&492=Z&496=Z&498=A&504=A&506=B&507=Z&514=D&518=B&519=Z&523=C&536=A&554=Z&557=Z&560=A&582=Z&584=A&586=Z&587=Z&588=B&591=C&599=A&603=Z&610=Z&614=B&625=A&664=A&666=C&668=C&670=Z&672=L&674=L&698=B&699=A&720=BB&745=Z&754=A&756=Z&759=Z&762=Z&766=AA&767=AA&769=A&772=HB&785=B&787=Z&788=Z&789=Z&790=Z&791=Z&792=Z&794=Z&795=A&796=Z&803=A&808=Z&809=DC&812=G&813=G&815=G&821=K&822=M&824=ES&828=Z&829=GA&831=SN&837=BC&841=K&845=K&851=S&852=Z&853=B&854=WU&855=B&856=WU&857=A&859=A&861=B&863=C&865=A&867=B&869=Z&873=ZA&882=CM&889=CD&921=Z&922=Z&924=Z&925=Z&932=B&933=Z&941=Z&952=RJ&954=Z&967=P&984=A&985=H&1002=D&1007=F&1041=F&1052=BR&1053=BR&1056=PD&1057=NA&1095=H&1104=B&1121=A&1122=M&1123=D&1162=G&1163=A&1164=B&1165=A&1166=E&1174=A&1182=A&1183=A&1185=C&1188=Z&1202=KG&1211=A&1223=B&1229=Z&1231=A&1233=Z&1237=L&1256=TW&1258=C&1259=BH&1260=D&1261=A&1272=C&1296=Z&1298=Z&1299=A&1302=A&1303=A&1308=C&1309=J&1313=A&1316=B&1317=Z&1318=A&1319=Z&1323=D&1327=A&1328=A&1329=Z&1330=Z&1331=A&1332=Z&1333=Z&1335=DS&1339=Z&1345=AE&1346=AG&1352=Z&1356=Z&1366=Z&1367=B&1368=B&1369=A&1370=W&1371=A&1373=Z&1379=GQ&1381=A&1387=CX&1388=Z&1389=EU&1391=E&1392=J&1397=Z&1399=Z&1401=Z&1405=A&1406=CN&1412=Z&1416=Z&1417=B&1419=Z&1421=Z&1424=Z&1428=Z&1431=B&1432=B&1436=A&1437=Z&1441=CB&1442=A&1443=Z&1449=A&1452=Z&1453=Z&1470=A&1473=Z&1474=A&1475=Z&1477=D&1478=B&1479=B&1481=A&1488=A&1490=D&1493=E&1494=Z&1502=Y&1503=BH&1504=C&1505=B&1506=Z&1511=Z&1512=A&1513=KU&1518=A&1524=Z&1541=A&1549=A&1554=A&1623=A&1629=Z&1637=B&1640=Z&1642=Z&1643=Z&1644=B&1661=A&1673=K&1681=A&1771=A&1772=Z&1787=Z&1788=Z&1790=Z&1793=Z&1837=A&1838=Z&1839=Z&1854=Z&1855=Z&1856=Z&1858=Z&1867=B&1872=B&1873=B&1879=Z&1881=B&1902=Z&1910=Z&1916=B&1917=A&1918=B&1920=A&1927=A&1928=Z&1963=Z&1964=Z&1968=A&1974=A&1975=Z&1976=Z&1993=Z&2007=A&2010=Z&2011=A&2012=Z&2015=Z&2022=Z&2023=Z&2024=Z&2032=Z&2037=Z&MPC-9002=AA&MPC-9006=AG&')
,(165,'1=A&2=R&4=B&33=G&34=Q&46=Y&49=A&75=AH&589=C&590=A&803=IG&812=RB&813=RB&814=RB&815=RB&841=V&843=V&844=V&845=V&851=S&853=B&854=KJ&855=B&856=KJ&857=B&858=KJ&859=B&860=KJ&861=B&862=RB&863=B&864=RB&865=B&866=RB&867=B&881=AC&883=GE&889=M&897=IS&922=C&965=CP&1323=C&');
DECLARE @tblB TABLE(ID INT,YourString VARCHAR(MAX));
INSERT INTO @tblB VALUES
(1,'1=A&1323=D!1=B&1323=D!1=A&1323=E!1=F&1323=D!1=B&1323=E!1=F&1323=E')
,(2,'1=B&142=D&1323=D&1470=B')
,(3,'1=A&1323=E&1470=C');
WITH tblA AS
(
SELECT ID
,A.[key] AS OrdPosition
,A.[value] AS Fragment
,x.value('/x[1]','varchar(10)') AS FragmentLeft
,x.value('/x[2]','varchar(10)') AS FragmentRight
FROM @tblA
CROSS APPLY OPENJSON('["' + REPLACE(YourString,'&','","') + '"]') A
CROSS APPLY(SELECT CAST('<x>' + REPLACE(A.[value],'=','</x><x>') + '</x>' AS XML)) B(x)
)
,tblB AS
(
SELECT ID
,A.[key] AS OrdPositionA
,B.[key] AS OrdPositionB
,B.[value] AS Fragment
,x.value('/x[1]','varchar(10)') AS FragmentLeft
,x.value('/x[2]','varchar(10)') AS FragmentRight
FROM @tblB
CROSS APPLY OPENJSON('["' + REPLACE(YourString,'!','","') + '"]') A
CROSS APPLY OPENJSON('["' + REPLACE(A.[value],'&','","') + '"]') B
CROSS APPLY(SELECT CAST('<x>' + REPLACE(B.[value],'=','</x><x>') + '</x>' AS XML)) C(x)
)
SELECT a.Fragment
,a.ID AS ID_a, a.OrdPosition AS OrdPosition_a
,b.ID AS ID_b, b.OrdPositionA AS OrdPosition_b1,b.OrdPositionB AS OrdPosition_b2
FROM tblA a
INNER JOIN tblB b ON a.FragmentLeft=b.FragmentLeft AND a.FragmentRight=b.FragmentRight;
结果
+----------+------+---------------+------+----------------+----------------+
| Fragment | ID_a | OrdPosition_a | ID_b | OrdPosition_b1 | OrdPosition_b2 |
+----------+------+---------------+------+----------------+----------------+
| 1=A | 123 | 0 | 1 | 0 | 0 |
+----------+------+---------------+------+----------------+----------------+
| 1=A | 165 | 0 | 1 | 0 | 0 |
+----------+------+---------------+------+----------------+----------------+
| 1=A | 123 | 0 | 1 | 2 | 0 |
+----------+------+---------------+------+----------------+----------------+
| 1=A | 165 | 0 | 1 | 2 | 0 |
+----------+------+---------------+------+----------------+----------------+
| 1=A | 123 | 0 | 3 | 0 | 0 |
+----------+------+---------------+------+----------------+----------------+
| 1=A | 165 | 0 | 3 | 0 | 0 |
+----------+------+---------------+------+----------------+----------------+
| 1323=D | 123 | 296 | 1 | 3 | 1 |
+----------+------+---------------+------+----------------+----------------+
| 1323=D | 123 | 296 | 1 | 1 | 1 |
+----------+------+---------------+------+----------------+----------------+
| 1323=D | 123 | 296 | 1 | 0 | 1 |
+----------+------+---------------+------+----------------+----------------+
| 1323=D | 123 | 296 | 2 | 0 | 2 |
+----------+------+---------------+------+----------------+----------------+
这样阅读：
片段1=A在a线123和165a中是常见的，而b线1或3在第一或第三块（从零开始的索引）中位于第一位置< / p>
片段1323=D在a线123和b线1和2中是常见的。它是a线和...（等等）中的第297个片段。 。）
如果这对您没有帮助：请提供预期的输出以及加入规则。
答案 1 :(得分：2)
在MS Sql Server 2016+中，您可以使用STRING_SPLIT函数从tableB中拆分字符串。
甚至是双重分割的em。
然后将这些字符串部分与TableA中的字符串进行匹配。
使用表变量进行演示的示例片段：
declare @TableA table (ID int primary key identity(1,1), [Str] varchar(3000));
declare @TableB table (ID int primary key identity(1,1), [Str] varchar(100));
insert into @TableA ([Str]) values
('1=A&3=B&8=B&11=A&12=R&17=BX&19=Z&20=B&21=AK&22=AH&24=A&27=A&28=A&29=C&31=A&32=S&33=N&34=H&35=Z&37=A&38=Z&39=A&41=D&42=G&49=A&52=Z&53=C&54=D&55=Z&56=Z&57=Z&58=A&61=B&63=B&65=A&66=A&67=A&68=A&69=A&71=G&73=Q&74=AB&76=B&77=Z&79=F&80=B&82=D&83=B&89=BA&91=Z&92=Z&93=Z&95=R&97=B&98=Z&99=G&100=G&101=B&106=C&109=Z&110=A&111=Z&112=C&116=B&118=Z&120=B&121=A&122=A&124=E&125=Z&128=A&131=Z&137=F&141=A&142=B&143=Z&144=B&146=C&148=Z&153=A&157=A&164=A&167=Z&168=Z&170=C&188=E&200=A&203=B&227=Z&235=C&237=B&238=G&258=Z&259=Z&268=Z&272=B&274=D&284=B&285=C&288=A&289=Z&290=A&299=M&300=D&313=Z&315=Z&322=A&324=Z&327=Z&358=E&360=B&365=A&366=A&375=B&376=B&379=Z&381=Z&383=M&387=Z&390=Z&391=Z&392=B&393=Z&398=MA&400=Z&403=B&404=A&407=B&408=BT&410=B&412=A&413=F&414=B&415=F&416=B&419=Z&421=Z&430=C&433=Z&435=C&440=Z&441=PG&448=A&453=A&458=B&459=Z&460=Z&463=A&466=Z&468=Z&472=Z&474=A&475=Z&492=Z&496=Z&498=A&504=A&506=B&507=Z&514=D&518=B&519=Z&523=C&536=A&554=Z&557=Z&560=A&582=Z&584=A&586=Z&587=Z&588=B&591=C&599=A&603=Z&610=Z&614=B&625=A&664=A&666=C&668=C&670=Z&672=L&674=L&698=B&699=A&720=BB&745=Z&754=A&756=Z&759=Z&762=Z&766=AA&767=AA&769=A&772=HB&785=B&787=Z&788=Z&789=Z&790=Z&791=Z&792=Z&794=Z&795=A&796=Z&803=A&808=Z&809=DC&812=G&813=G&815=G&821=K&822=M&824=ES&828=Z&829=GA&831=SN&837=BC&841=K&845=K&851=S&852=Z&853=B&854=WU&855=B&856=WU&857=A&859=A&861=B&863=C&865=A&867=B&869=Z&873=ZA&882=CM&889=CD&921=Z&922=Z&924=Z&925=Z&932=B&933=Z&941=Z&952=RJ&954=Z&967=P&984=A&985=H&1002=D&1007=F&1041=F&1052=BR&1053=BR&1056=PD&1057=NA&1095=H&1104=B&1121=A&1122=M&1123=D&1162=G&1163=A&1164=B&1165=A&1166=E&1174=A&1182=A&1183=A&1185=C&1188=Z&1202=KG&1211=A&1223=B&1229=Z&1231=A&1233=Z&1237=L&1256=TW&1258=C&1259=BH&1260=D&1261=A&1272=C&1296=Z&1298=Z&1299=A&1302=A&1303=A&1308=C&1309=J&1313=A&1316=B&1317=Z&1318=A&1319=Z&1323=D&1327=A&1328=A&1329=Z&1330=Z&1331=A&1332=Z&1333=Z&1335=DS&1339=Z&1345=AE&1346=AG&1352=Z&1356=Z&1366=Z&1367=B&1368=B&1369=A&1370=W&1371=A&1373=Z&1379=GQ&1381=A&1387=CX&1388=Z&1389=EU&1391=E&1392=J&1397=Z&1399=Z&1401=Z&1405=A&1406=CN&1412=Z&1416=Z&1417=B&1419=Z&1421=Z&1424=Z&1428=Z&1431=B&1432=B&1436=A&1437=Z&1441=CB&1442=A&1443=Z&1449=A&1452=Z&1453=Z&1470=A&1473=Z&1474=A&1475=Z&1477=D&1478=B&1479=B&1481=A&1488=A&1490=D&1493=E&1494=Z&1502=Y&1503=BH&1504=C&1505=B&1506=Z&1511=Z&1512=A&1513=KU&1518=A&1524=Z&1541=A&1549=A&1554=A&1623=A&1629=Z&1637=B&1640=Z&1642=Z&1643=Z&1644=B&1661=A&1673=K&1681=A&1771=A&1772=Z&1787=Z&1788=Z&1790=Z&1793=Z&1837=A&1838=Z&1839=Z&1854=Z&1855=Z&1856=Z&1858=Z&1867=B&1872=B&1873=B&1879=Z&1881=B&1902=Z&1910=Z&1916=B&1917=A&1918=B&1920=A&1927=A&1928=Z&1963=Z&1964=Z&1968=A&1974=A&1975=Z&1976=Z&1993=Z&2007=A&2010=Z&2011=A&2012=Z&2015=Z&2022=Z&2023=Z&2024=Z&2032=Z&2037=Z&MPC-9002=AA&MPC-9006=AG&')
,('1=A&2=R&4=B&33=G&34=Q&46=Y&49=A&75=AH&589=C&590=A&803=IG&812=RB&813=RB&814=RB&815=RB&841=V&843=V&844=V&845=V&851=S&853=B&854=KJ&855=B&856=KJ&857=B&858=KJ&859=B&860=KJ&861=B&862=RB&863=B&864=RB&865=B&866=RB&867=B&881=AC&883=GE&889=M&897=IS&922=C&965=CP&1323=C&')
;
insert into @TableB ([Str]) values
('1=A&1323=D!1=B&1323=D!1=A&1323=E!1=F&1323=D!1=B&1323=E!1=F&1323=E')
,('1=B&142=D&1323=D&1470=B')
,('1=A&1323=E&1470=C')
;
select A.ID as ID1, ssB.ID as ID2
-- , COUNT(DISTINCT ssB.StrPart) as TotalStringPartsMatching
-- , STRING_AGG(ssB.StrPart, '&') WITHIN GROUP (ORDER BY ssB.StrPart) as CommonStrParts
from @TableA A
left join
(
select distinct B.ID, ss2.value as StrPart
from @TableB B
cross apply string_split([Str],'!') ss1
cross apply string_split(ss1.value,'&') ss2
) ssB on concat('&',A.[Str],'&') like concat('%&',ssb.StrPart,'&%')
group by A.ID, ssB.ID;
结果：
ID1 ID2
1 1
1 2
1 3
2 1
2 3
答案 2 :(得分：1)
由于LukStorms提供了非常有趣的解决方案，并且我们在对他的解决方案的评论中进行了讨论，因此我不确定这是最好的选择，但... CTE应该胜任。
注意：：我没有MS SQL Server 2017，因此我使用了CHARINDEX函数将字符串拆分为多个部分并进行比较。
在这里：
DECLARE @Equip TABLE(ID INT, StrData VARCHAR(8000))
INSERT INTO @Equip (ID, StrData )
VALUES(123, '1=A&3=B&8=B&11=A&12=R&17=BX&19=Z&20=B&21=AK&22=AH&24=A&27=A&28=A&29=C&31=A&32=S&33=N&34=H&35=Z&37=A&38=Z&39=A&41=D&42=G&49=A&52=Z&53=C&54=D&55=Z&56=Z&57=Z&58=A&61=B&63=B&65=A&66=A&67=A&68=A&69=A&71=G&73=Q&74=AB&76=B&77=Z&79=F&80=B&82=D&83=B&89=BA&91=Z&92=Z&93=Z&95=R&97=B&98=Z&99=G&100=G&101=B&106=C&109=Z&110=A&111=Z&112=C&116=B&118=Z&120=B&121=A&122=A&124=E&125=Z&128=A&131=Z&137=F&141=A&142=B&143=Z&144=B&146=C&148=Z&153=A&157=A&164=A&167=Z&168=Z&170=C&188=E&200=A&203=B&227=Z&235=C&237=B&238=G&258=Z&259=Z&268=Z&272=B&274=D&284=B&285=C&288=A&289=Z&290=A&299=M&300=D&313=Z&315=Z&322=A&324=Z&327=Z&358=E&360=B&365=A&366=A&375=B&376=B&379=Z&381=Z&383=M&387=Z&390=Z&391=Z&392=B&393=Z&398=MA&400=Z&403=B&404=A&407=B&408=BT&410=B&412=A&413=F&414=B&415=F&416=B&419=Z&421=Z&430=C&433=Z&435=C&440=Z&441=PG&448=A&453=A&458=B&459=Z&460=Z&463=A&466=Z&468=Z&472=Z&474=A&475=Z&492=Z&496=Z&498=A&504=A&506=B&507=Z&514=D&518=B&519=Z&523=C&536=A&554=Z&557=Z&560=A&582=Z&584=A&586=Z&587=Z&588=B&591=C&599=A&603=Z&610=Z&614=B&625=A&664=A&666=C&668=C&670=Z&672=L&674=L&698=B&699=A&720=BB&745=Z&754=A&756=Z&759=Z&762=Z&766=AA&767=AA&769=A&772=HB&785=B&787=Z&788=Z&789=Z&790=Z&791=Z&792=Z&794=Z&795=A&796=Z&803=A&808=Z&809=DC&812=G&813=G&815=G&821=K&822=M&824=ES&828=Z&829=GA&831=SN&837=BC&841=K&845=K&851=S&852=Z&853=B&854=WU&855=B&856=WU&857=A&859=A&861=B&863=C&865=A&867=B&869=Z&873=ZA&882=CM&889=CD&921=Z&922=Z&924=Z&925=Z&932=B&933=Z&941=Z&952=RJ&954=Z&967=P&984=A&985=H&1002=D&1007=F&1041=F&1052=BR&1053=BR&1056=PD&1057=NA&1095=H&1104=B&1121=A&1122=M&1123=D&1162=G&1163=A&1164=B&1165=A&1166=E&1174=A&1182=A&1183=A&1185=C&1188=Z&1202=KG&1211=A&1223=B&1229=Z&1231=A&1233=Z&1237=L&1256=TW&1258=C&1259=BH&1260=D&1261=A&1272=C&1296=Z&1298=Z&1299=A&1302=A&1303=A&1308=C&1309=J&1313=A&1316=B&1317=Z&1318=A&1319=Z&1323=D&1327=A&1328=A&1329=Z&1330=Z&1331=A&1332=Z&1333=Z&1335=DS&1339=Z&1345=AE&1346=AG&1352=Z&1356=Z&1366=Z&1367=B&1368=B&1369=A&1370=W&1371=A&1373=Z&1379=GQ&1381=A&1387=CX&1388=Z&1389=EU&1391=E&1392=J&1397=Z&1399=Z&1401=Z&1405=A&1406=CN&1412=Z&1416=Z&1417=B&1419=Z&1421=Z&1424=Z&1428=Z&1431=B&1432=B&1436=A&1437=Z&1441=CB&1442=A&1443=Z&1449=A&1452=Z&1453=Z&1470=A&1473=Z&1474=A&1475=Z&1477=D&1478=B&1479=B&1481=A&1488=A&1490=D&1493=E&1494=Z&1502=Y&1503=BH&1504=C&1505=B&1506=Z&1511=Z&1512=A&1513=KU&1518=A&1524=Z&1541=A&1549=A&1554=A&1623=A&1629=Z&1637=B&1640=Z&1642=Z&1643=Z&1644=B&1661=A&1673=K&1681=A&1771=A&1772=Z&1787=Z&1788=Z&1790=Z&1793=Z&1837=A&1838=Z&1839=Z&1854=Z&1855=Z&1856=Z&1858=Z&1867=B&1872=B&1873=B&1879=Z&1881=B&1902=Z&1910=Z&1916=B&1917=A&1918=B&1920=A&1927=A&1928=Z&1963=Z&1964=Z&1968=A&1974=A&1975=Z&1976=Z&1993=Z&2007=A&2010=Z&2011=A&2012=Z&2015=Z&2022=Z&2023=Z&2024=Z&2032=Z&2037=Z&MPC-9002=AA&MPC-9006=AG&'),
(165, '1=A&2=R&4=B&33=G&34=Q&46=Y&49=A&75=AH&589=C&590=A&803=IG&812=RB&813=RB&814=RB&815=RB&841=V&843=V&844=V&845=V&851=S&853=B&854=KJ&855=B&856=KJ&857=B&858=KJ&859=B&860=KJ&861=B&862=RB&863=B&864=RB&865=B&866=RB&867=B&881=AC&883=GE&889=M&897=IS&922=C&965=CP&1323=C&')
DECLARE @Another TABLE(ID INT, StrData VARCHAR(8000))
INSERT INTO @Another (ID, StrData )
VALUES(1, '1=A&1323=D!1=B&1323=D!1=A&1323=E!1=F&1323=D!1=B&1323=E!1=F&1323=E'),
(2, '1=B&142=D&1323=D&1470=B'),
(3, '1=A&1323=E&1470=C')
;WITH E AS
(
--inital part
SELECT 1 AS Step, ID, LEFT(StrData, CHARINDEX('&', StrData) -1) AS Part, RIGHT(StrData, LEN(StrData) - CHARINDEX('&', StrData)) AS Remainder
FROM @Equip
WHERE CHARINDEX('&', StrData)>0
-- recursive part
UNION ALL
SELECT Step+1 AS Step, ID, LEFT(Remainder, CHARINDEX('&', Remainder) -1) AS Part, RIGHT(Remainder, LEN(Remainder) - CHARINDEX('&', Remainder)) AS Remainder
FROM E
WHERE CHARINDEX('&', Remainder)>0
UNION ALL
SELECT Step+1 AS Step, ID, Remainder AS Part, NULL AS Remainder
FROM E
WHERE CHARINDEX('&', Remainder)=0
),
A AS
(
--inital part
SELECT 1 AS Step, ID, LEFT(StrData, CHARINDEX('!', StrData) -1) AS Part, RIGHT(StrData, LEN(StrData) - CHARINDEX('!', StrData)) AS Remainder
FROM @Another
WHERE CHARINDEX('!', StrData)>0
-- recursive part
UNION ALL
SELECT Step+1 AS Step, ID, LEFT(Remainder, CHARINDEX('!', Remainder) -1) AS Part, RIGHT(Remainder, LEN(Remainder) - CHARINDEX('!', Remainder)) AS Remainder
FROM A
WHERE CHARINDEX('!', Remainder)>0
UNION ALL
SELECT Step+1 AS Step, ID, Remainder AS Part, NULL AS Remainder
FROM A
WHERE CHARINDEX('!', Remainder)=0
)
SELECT E.ID AS EID, E.Step AS EStep, E.Part AS EPart, A.ID AS AID, A.Part AS APart, CHARINDEX(E.Part, A.Part) AS Result
FROM E CROSS JOIN A
WHERE CHARINDEX(E.Part, A.Part)>0
OPTION (MAXRECURSION 0)
结果：
EID EStep EPart AID APart Result
123 1 1=A 1 1=A&1323=D 1
123 1 1=A 1 1=A&1323=E 1
165 1 1=A 1 1=A&1323=D 1
165 1 1=A 1 1=A&1323=E 1
123 297 1323=D 1 1=A&1323=D 5
123 297 1323=D 1 1=B&1323=D 5
123 297 1323=D 1 1=F&1323=D 5
祝你好运！