Question

我正在使用 webview 在android studio中创建一个应用，我想要这样的东西。 “如果该网址无法加载并显示屏幕截图之类的内容，则我的应用将显示一个吐司，提示不正确的网址。”如果网址正确加载，则吐司将显示正确的网址。

我该怎么做。

MainActivity.Java

public class MainActivity extends AppCompatActivity {

WebView mWebv;
ProgressBar spinner;
private String main_url = "http://my.wifi/";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    getSupportActionBar().hide();
    setContentView(R.layout.activity_main);

    spinner = findViewById(R.id.webview_spinner);

    mWebv = findViewById(R.id.web_view);
    WebSettings settings = mWebv.getSettings();
    settings.setJavaScriptEnabled(true);


    mWebv.setWebViewClient(new WebViewClient(){

        @Override
        public void onPageStarted(WebView view, String url, Bitmap favicon) {
            super.onPageStarted(view, url, favicon);
            spinner.setVisibility(View.VISIBLE);
        }
        @Override
        public void onPageFinished(WebView view, String url) {
            super.onPageFinished(view, url);
            spinner.setVisibility(View.GONE);
        }
    });
    mWebv.getSettings().setJavaScriptEnabled(true);
    mWebv.loadUrl(main_url);
}
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
    if (event.getAction() == KeyEvent.ACTION_DOWN) {
        switch (keyCode) {
            case KeyEvent.KEYCODE_BACK:
                if (mWebv.canGoBack()) {
                    mWebv.goBack();
                } else {
                    finish();
                }
                return true;
        }
    }
    return super.onKeyDown(keyCode, event);
}

Answer 1

只需将此方法重写到您的setWebViewClient中即可

 mWebv.setWebViewClient(new WebViewClient(){
    ...
    @SuppressWarnings("deprecation")
    @Override
    public void onReceivedError(WebView view, int errorCode, String description, String failingUrl)
    {
    // do some stuff
    }

    @TargetApi(android.os.Build.VERSION_CODES.M)
    @Override
    public void onReceivedError(WebView inView, WebResourceRequest inReq,WebResourceError inError) 
    {
    // do some stuff
    onReceivedError(inView, inError.getErrorCode(), inError.getDescription().toString(), inReq.getUrl().toString());
    }
});

感谢@ newton_cr7提出修改建议

使用WebView检查URL

1 个答案: