我正在尝试将下面的函数转换为使用.some()方法,但我不知道这是如何工作的。我已经阅读了MDN文档。 谁能帮我吗?
function guessRepeatValidate(userGuess) {
let passed = true;
if (guessArchive.indexOf(userGuess) > -1) {
passed = false;
}
return passed;
}
答案 0 :(得分:0)
这里是如何转换。
let guessArchive = ['test', 'some'];
function guessRepeatValidate(userGuess) {
return !guessArchive.some(i => i===userGuess);
}
console.log(guessRepeatValidate('test'));
console.log(guessRepeatValidate('blah'));
答案 1 :(得分:0)
const guessRepeatValidate = (userGuess, guessArchive) => !guessArchive.some(i => i === userGuess);
const guessArchive = ['one', 'two', 'three'];
console.log(guessRepeatValidate('one', guessArchive));
console.log(guessRepeatValidate('four', guessArchive));
答案 2 :(得分:0)
对于这种问题,可以接受的做法是使用includes
,但是,如果您真的想使用some
:
function guessRepeatValidate(userGuess) {
return !guessArchive.some(e => e == userGuess);
}