Question

我有一个非常小的程序，它将字符串转换为double。问题是每次打印0.0000。请帮帮我。

提前致谢。

enter code here

$ export LT_LEAK_START=1.5
$ echo $LT_LEAK_START
  1.5

#include <stdio.h>

int main()
{
  double d;
  d=strtod(getenv("LT_LEAK_START"), NULL);
  printf("d = %lf\n",d);
}
Output:
d=0.0000000

Answer 1

尝试包含

#include <stdlib.h>

Answer 2

你没有包含strtod decl头文件（stdlib.h）所以你使用的是内部strtod实现（它似乎只是一个存根？）

root@pinkpony:~# gcc -Wall -g  -o t t.c
t.c: In function ‘main’:
t.c:6: warning: implicit declaration of function ‘strtod’
t.c:6: warning: implicit declaration of function ‘getenv’
t.c:8: warning: control reaches end of non-void function
root@pinkpony:~# gdb ./t
Reading symbols from /root/t...done.
(gdb) run
Starting program: /root/t 

Program received signal SIGSEGV, Segmentation fault.
0x00007ffff7a96b64 in ____strtod_l_internal (nptr=<value optimized out>, endptr=<value optimized out>, group=<value optimized out>, loc=0x7ffff7dd6580) at strtod_l.c:530
5    30     strtod_l.c: No such file or directory.
        in strtod_l.c
(gdb) bt
#0  0x00007ffff7a96b64 in ____strtod_l_internal (nptr=<value optimized out>, endptr=<value optimized out>, group=<value optimized out>, loc=0x7ffff7dd6580) at strtod_l.c:530
#1  0x00000000004005bc in main () at t.c:6
(gdb)

忽略sigsegv，在我的平台上是由getenv（）引起的，它在stdlib中声明但没有内部gcc impl

strtod - 将字符串转换为double的问题

2 个答案: