Question

我正在向Python Stripe API提出所有争议。我当前用于检索所有争议的代码如下。

import stripe

stripe.api_key = "12345"

disputes = stripe.Dispute.list(limit=100)

但是，我只想请求包含status中的needs_response的争议。在Stripe API中是否有特定的方法来请求这些争议？

Answer 1

您最好的选择是从API检索disputes的完整列表后，在本地进行过滤。使用auto-pagination，这可以很简单：

disputes = stripe.Dispute.list(limit=3)

for dispute in disputes.auto_paging_iter():
    if (dispute.status == 'needs_response'):
        # Do something with the dispute

作为概括，如果不在arguments list for that resource中，则只想在本地进行任何进一步的过滤。

Answer 2

import stripe
stripe.api_key = get_stripe()
from datetime import datetime, timedelta
import delorean
dt = datetime.utcnow()
lte = delorean.Delorean(dt, timezone="UTC").epoch
a =  datetime.now() + timedelta(days=-2)
gte = delorean.Delorean(a, timezone="UTC").epoch
chuck = stripe.Dispute.list(created={'gte':int(gte),'lte':int(lte)})
print "NUMBER OF DISPUTES:", len(chuck)

ch_lst = []
id_lst = []
name_lst = []
am_lst = []
f_lst = []


for d in chuck.auto_paging_iter():
    for d in chuck.auto_paging_iter():
        if (d['status'] == 'needs_response' or d['status'] == 'warning_needs_response'):
        c = stripe.Charge.retrieve(str(d['charge']))
        ch_lst.append(str(d['charge']))
        id_lst.append(str(d['id']))
        am_lst.append(str(c['amount']))
        name_lst.append(str(c['source']['name']))
        f_lst.append(str(c['source']['fingerprint']))

Stripe API-过滤争议请求

2 个答案: