Question

我想使用re.findall()来匹配评论网站中的公司名称实例。例如，我想捕获列表中的名称，如以下示例中的名称：

website_html = ', Jimmy Bob's Tune & Lube, Allen's Bar & Grill, Joanne's - Restaurant,'
name_list = re.findall('[,]\s*([\w\'&]*\s?)*[,]', website_html)

我的代码没有捕获任何模式。有什么想法吗？

Answer 1

您仅提供了一个输入示例，因此此答案是基于您的问题的：

# I replace the single quotes at the start and end of your input, because 
# Bob's throws a SyntaxError: invalid syntax
# 
website_html = ", Jimmy Bob's Tune & Lube,"

# I removed re.findall, because you only had one example so re.search or 
# re.match works.  
name_list = re.search(r'[,]\s*([\w\'&]*\s?)*[,]', website_html)

print (name_list.group(0))
# output
, Jimmy Bob's Tune & Lube,

如果您在website_html中还有其他输入值，请提供它们，以便我修改答案。

这是使用re.findall的版本。

# I replace the single quotes at the start and end of your input, because 
# Bob's throws a SyntaxError: invalid syntax
# 
website_html = ", Jimmy Bob's Tune & Lube,"

# I wrapped your pattern as a capture group
name_list = re.findall(r'([,]\s*([\w\'&]*\s?)*[,])', website_html)

print (type(name_list))
# output 
<class 'list'>

print (name_list)
# output 
[(", Jimmy Bob's Tune & Lube,", '')]

更新后的答案

此答案基于对原始问题的修改输入。

website_html = ", Jimmy Bob's Tune & Lube, Allen's Bar & Grill, Joanne's - Restaurant,"
name_list = re.findall(r'[?:,].*[?:,]', website_html)
for item in name_list:
  split_strings = (str(item).split(','))
  for string in split_strings:
     print (string)

     # output 
     Jimmy Bob's Tune & Lube
     Allen's Bar & Grill
     Joanne's - Restaurant

使用re.findall匹配html中的字符串

1 个答案: