我从原始帖子中重新措辞： 我有两个XML文件，它们分别与给定的年份有关。例如18/19和17/18。它们符合相同的结构，下面是这些文件之一的小样本。我想要的是，在C＃中，比较这些文件中的所有记录，其中给定名称，姓氏，NI编号和出生日期相同，但学习者编号则不同。我需要能够进行比较，然后仅将这些记录推送到数据表中，以便随后将它们推送到电子表格中（我可以做的电子表格位）。我目前将以下内容作为起点，但仍然非常困难。
首先，我需要按下导入按钮：
private void Btn_Import_Click(object sender, RoutedEventArgs e)
{
ILRChecks.ILRReport.CrossYear();}
然后看一下Class，最终将文件推送到我的位置：
using System.Data;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using ILRValidation;
using InfExcelExtension;
namespace ILRChecks
{
internal static partial class ILRReport
{
internal static void CrossYear()
{
DataSet ds_CrossYearChecks =
ILRValidation.Validation.CrossYearChecks(Global.fileNames);
string output = Path.Combine(Global.foldername, "ULIN_Issues" +
".xlsx");
ds_CrossYearChecks.ToWorkBook(output);
}
}
}
这就是我要坚持的一点，它是发现差异的结果：
using System;
using System.Collections.Generic;
using System.Data;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace ILRValidation
{
public static partial class Validation
{
public static DataSet CrossYearChecks(DataSet ds_CrossYearChecks)
{
return CrossYearChecks(ds_CrossYearChecks);
}
public static DataSet CrossYearChecks(string[] xmlPath)
{
DataSet ds_xmlCrossYear = new DataSet();
return CrossYearChecks(ds_xmlCrossYear);
}
}
}
XML：
<Learner>
<LearnRefNumber></LearnRefNumber>
<ULN></ULN>
<FamilyName></FamilyName>
<GivenNames></GivenNames>
<DateOfBirth></DateOfBirth>
<Ethnicity></Ethnicity>
<Sex></Sex>
<LLDDHealthProb></LLDDHealthProb>
<NINumber></NINumber>
<PriorAttain></PriorAttain>
<MathGrade></MathGrade>
<EngGrade></EngGrade>
<PostcodePrior></PostcodePrior>
<Postcode></Postcode>
<AddLine1></AddLine1>
<AddLine3></AddLine3>
<Email></Email>
答案 0 :(得分：1)
好吧，您可以递归地遍历两个XML文件并写下所有遇到的更改。诸如此类的东西应该会有所帮助：
static string AppendPrefix(string oldPrefix, string addition) =>
oldPrefix == "" ? addition : $"{oldPrefix}.{addition}";
static void CompareElements(string prefix, XElement d1, XElement d2)
{
// 1. compare names
var newPrefix = AppendPrefix(prefix, d1.Name.ToString());
if (d1.Name != d2.Name)
{
Console.WriteLine(
$"Name mismatch: {newPrefix} != {AppendPrefix(prefix, d2.Name.ToString())}");
return;
}
// 2. compare attributes
var attrs = d1.Attributes().OrderBy(a => a.Name);
var unpairedAttributes = new HashSet<XAttribute>(d2.Attributes());
foreach (var attr in attrs)
{
var otherAttr = d2.Attributes(attr.Name).SingleOrDefault();
if (otherAttr == null)
{
Console.WriteLine($"No new attr: {newPrefix}/{attr.Name}");
continue;
}
unpairedAttributes.Remove(otherAttr);
if (attr.Value != otherAttr.Value)
Console.WriteLine(
$"Attr value mismatch: {newPrefix}/{attr.Name}: {attr.Value} != {otherAttr.Value}");
}
foreach (var attr in unpairedAttributes)
Console.WriteLine($"No old attr: {newPrefix}/{attr.Name}");
// 3. compare subelements
var leftNodes = d1.Nodes().ToList();
var rightNodes = d2.Nodes().ToList();
var smallerCount = Math.Min(leftNodes.Count, rightNodes.Count);
for (int i = 0; i < smallerCount; i++)
CompareNodes(newPrefix, i, leftNodes[i], rightNodes[i]);
if (leftNodes.Count > smallerCount)
Console.WriteLine($"Extra {leftNodes.Count - smallerCount} nodes at old file");
if (rightNodes.Count > smallerCount)
Console.WriteLine($"Extra {rightNodes.Count - smallerCount} nodes at new file");
}
static void CompareNodes(string prefix, int index, XNode n1, XNode n2)
{
if (n1.NodeType != n2.NodeType)
{
Console.WriteLine($"Node type mismatch: {prefix}/[{index}]");
return;
}
switch (n1.NodeType)
{
case XmlNodeType.Element:
CompareElements(prefix, (XElement)n1, (XElement)n2);
break;
case XmlNodeType.Text:
CompareText(prefix, index, (XText)n1, (XText)n2);
break;
}
}
static void CompareText(string prefix, int index, XText t1, XText t2)
{
if (t1.Value != t2.Value)
Console.WriteLine($"Text mismatch at {prefix}[{index}]");
}
用法：
XDocument d1 = <get document #1 from somewhere>,
d2 = <get document #2 from somewhere>;
CompareNodes("", 0, d1.Root, d2.Root);
很明显，您不必写到控制台，而应该写到适当的电子表格。
请注意，我忽略的是属性重新排序，而不是子节点重新排序（这似乎是正确的）。
答案 1 :(得分：0)
在我看来，您在从xml提取所需的值时遇到问题，对吗？
正如其他人在评论中提到的那样，在不知道xml布局的情况下，不可能为您的案例提供具体的示例。如果您编辑问题以包含xml示例，我们将为您提供更多帮助。
以下是一些有关如何从xml中提取值的常规示例：
private static bool CheckXmlDocument(string xmlPathCheck)
{
// if you have multiple files from which you need to extract values, pass in an array or List<string> and loop over it, fetching the values
// XmlDocument will allow you to edit the document as well as read it
// there's another option to use XPathDocument and XPathNavigator but it's read-only
var doc = new XmlDocument();
// this can throw various exceptions so might want to add some handling
doc.Load(xmlPathCheck);
// getting the elements, you have some options depending on the layout of the document
// if the nodes you want are identified by 'id' use this:
var nameElement = doc.GetElementById("name");
// if the nodes you want are identified by 'tag', use this:
var nameNodeList = doc.GetElementsByTagName("name");
// if you know the xpath to the specific node you want, use this:
var selectNameNode = doc.SelectSingleNode("the/xpath/to/the/node");
// if there are several nodes that have the same xpaths, use this:
var selectNameList = doc.SelectNodes("the/xpath/that/may/match/many/nodes");
// getting the value depends on the if you have an XmlNode, XmlElement or XmlNodeList
// if you have a single XmlElement or XmlNode you can get the value one of these ways depending on the layout of your document:
var name = nameElement.InnerText;
name = nameElement.InnerXml;
// if you have an XmlNodeList, you'll have to iterate through the nodes to find the one you want, like this:
foreach (var node in nameNodeList)
{
// here use some condition that will determine if its the element/node you want or not (depends on your xml layout)
if (node is XmlNode n)
{
name = n.InnerText;
}
}
// do that for all the values you want to compare, then compare them
return CheckValues(/*the values to compare*/);
}