如何基于SQL中的另一列获取列中的递增值

Question

我有下表记录。对于每一个TranNo，我都必须在预期结果列中增加1。有可能吗？

如何在sqlserver中获得此结果？

我无法获得适当的结果

 <Expected Result>
1
1
2
3
4
5
6
7
8

我尝试过：

SELECT BatchNo,
       TranNo,
       WorkSource
FROM table1 WITH (NOLOCK)
WHERE BatchNo IN ('0000000420', '0000000421', '0000000422')
  AND PROCESSDATE = '20190206'
GROUP BY WorkSource,
         BATCHNO,
         TranNo;

Answer 1

您可以尝试

create table #temp (WorkSource char(3), BatchNo char(3), TranNo int)
insert into #temp values
('012', '001', 1),
('012', '001', 1),
('012', '001', 2),
('012', '001', 3),
('012', '002', 1),
('012', '002', 2),
('012', '003', 3),
('013', '005', 1),
('013', '005', 2)

SELECT *, Dense_Rank() OVER(ORDER BY BatchNo, TranNo) AS Row_Number  
FROM #temp

Answer 2

尝试一下：

;WITH LagTranNo AS
(
    SELECT 
        *, 
        IsDiffTranNo = CASE WHEN TranNo =  LAG(TranNo) OVER (ORDER BY WorkSource, BatchNo, TranNo) THEN 0 ELSE 1 END
    FROM 
        YourTable
)
SELECT
    L.*,
    SUM(L.IsDiffTranNo) OVER (ORDER BY WorkSource, BatchNo, TranNo)
FROM
    LagTranNo AS L

我相信您只想在TranNo更改时加1。订购时要小心。

注意：LAG仅适用于SQL Server 2012 +。