我正在尝试从数据库中获取出生日期并将其显示在JFormattedTextField上。它应以mm / dd / yyyy格式显示,但以yyyy / dd / mm格式存储。我将如何处理?患者的出生日期存储为java.sql.Date
JLabel lbl3 = new JLabel("Date of Birth:");
lbl3.setBounds(17, 129, 90, 22);
lbl3.setForeground(Color.WHITE);
lbl3.setFont(new Font("Microsoft New Tai Lue", Font.PLAIN, 16));
JFormattedTextField formattedDob = new JFormattedTextField();
formattedDob.setEditable(false);
formattedDob.setText("//");
formattedDob.setBounds(201, 128, 183, 22);
contentPane.add(formattedDob);
JButton btnSearchPatient = new JButton("Search");
btnSearchPatient.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
PatientSQL searchPatient = new PatientSQL();
Patient staff = searchPatient.getBySSN(patient.getSsn());
txtAddress1.setText(staff.getAddress1());
txtAddress2.setText(staff.getAddress2());
txtCity.setText(staff.getCity());
}
});
这是我的PatientSQL.java供参考(不相关的代码,例如软件包和函数已删除,以便于阅读):
public class PatientSQL {
private SessionFactory factory;
public PatientSQL() {
try {
factory = new Configuration().configure().buildSessionFactory();
} catch (Throwable ex) {
System.err.println("Failed to create sessionFactory object." + ex);
throw new ExceptionInInitializerError(ex);
}
}
/* Method to CREATE a patient in the database */
public void add(String fname, String lname, String ssn, java.sql.Date dob, String phoneNo, String address1, String address2, String city, String zipcode, String allergy1, String allergy2, String allergy3, String photo) {
Patient patient = new Patient(fname, lname, ssn, dob, phoneNo, address1, address2, city, zipcode, allergy1, allergy2, allergy3, photo);
add(patient);
}
public Patient getBySSN(String ssn) {
Session session = factory.openSession();
Patient patient = null;
try {
patient = (Patient) session.get(Patient.class, ssn);
} catch (HibernateException e) {
System.err.println("Can not find patient ssn: " + ssn);
} finally {
session.close();
}
return patient;
}
}
答案 0 :(得分:0)
也许您应该尝试转换日期: 使用LocalDateTime#parse()(如果字符串恰巧包含时区部分,则使用ZonedDateTime#parse())将特定模式的String解析为LocalDateTime。 喜欢:
String date_s = "2011/01/18";
SimpleDateFormat dt = new SimpleDateFormat("yyyy/dd/mm");
Date date = dt.parse(date_s);
SimpleDateFormat dt1 = new SimpleDateFormat("mm/dd/yyyy");
System.out.println(dt1.format(date));
答案 1 :(得分:0)
愚蠢的要求要求愚蠢的答案:
CREATE TABLE patient (
...
dob_string VARCHAR(8),
dob_date DATE AS (STR_TO_DATE(dob_string,"%Y/%d/%m"))
)
因此,将其存储到dob_string
中,然后从dob_date
获取,然后根据需要输出格式。
答案 2 :(得分:0)
如果可以使用SimpleDateFormat
SimpleDateFormat df = new SimpleDateFormat("MM/dd/yyyy");
df.format(patient.getDob()); //I'm guessing what the get method is named but you get what I mean