Question

所以我希望此代码以不同的方式打印：

Python代码：

employees = {123: 'Bob', 124: 'Susan', 128: 'Abby', 125: 'Henry', 126: 'Edward', 127: 'James'}

for key in employees.keys():
    print("Employees Numbers: ", key)

for value in employees.values():
    print("Employee Names: ", value)

打印为：

Employees Numbers:  123                      
Employees Numbers:  124             
Employees Numbers:  128                         
Employees Numbers:  125                
Employees Numbers:  126            
Employees Numbers:  127              
Employee Names:  Bob                
Employee Names:  Susan               
Employee Names:  Abby              
Employee Names:  Henry             
Employee Names:  Edward             
Employee Names:  James

希望将其打印为：

Employee Numbers: 123, 124, 128, 125, 126, 127                     
Employee Names: Bob, Susan, Abby, Henry, Edward

Answer 1

您可以像这样循环浏览这些键：

print('Employee Numbers: {}'.format(', '.join(str(num) for num in employees.keys())))

然后类似地输入名称：

print('Employee Names: {}'.format(', '.join(name for name in employees.values())))

Answer 2

您可以循环浏览字典并使用格式化的字符串进行显示

>>> employees = {123: 'Bob', 124: 'Susan', 128: 'Abby', 125: 'Henry', 126: 'Edward', 127: 'James'}
>>> print('Employee Numbers: {}'.format(', '.join(str(key) for key in employees.keys())))
Employee Numbers: 128, 123, 124, 125, 126, 127
>>> print('Employee Names: {}'.format(', '.join(value for value in employees.values())))
Employee Names: Abby, Bob, Susan, Henry, Edward, James

Answer 3

首先将keys和values存储到单独的lists中，然后使用join运算符将它们填充到由string分隔的comma中。

对于员工编号，您需要执行一个额外的步骤，将编号转换为strings（因为join仅在string上起作用）

employees = {123: 'Bob', 124: 'Susan', 128: 'Abby', 125: 'Henry', 126: 'Edward', 127: 'James'}

numbers = list(employees.keys())
names = list(employees.values())

print("Employee Keys : ",', '.join([str(i) for i in numbers]))
print("Employee Names : ",', '.join(names))

Answer 4

#!/usr/bin/env python


def main():
    employees = {123: 'Bob', 124: 'Susan', 128: 'Abby', 125: 'Henry', 126: 'Edward', 127: 'James'}

    print("employees ids:", ", ".join([str(x) for x in employees]))
    print("employees names:", ", ".join([str(x) for x in employees.values()]))


if __name__ == '__main__':
    main()

输出：

employees ids: 123, 124, 128, 125, 126, 127
employees names: Bob, Susan, Abby, Henry, Edward, James

Answer 5

employees = {123: 'Bob', 124: 'Susan', 128: 'Abby', 125: 'Henry', 126: 'Edward', 127: 
'James'}


a=list(employees.keys())
str1=", ".join(str(e) for e in a)
print("Employee Numbers:",str1)


b=list(employees.values())
str2=", ".join(b)
print("Employee Names:",str2)

键和值在Python中分别打印，但要附加到字符串

5 个答案: