在此查询中,我还想在同一查询中选择第三列wp_postmeta.post_id
。如果不通过涉及子查询的JOIN附加它,我无法弄清楚该如何做。没有使用子查询,难道没有更简单的方法吗? (如果解决方案有效且不会占用过多资源,则将让步子查询。)
MariaDB 10.1
create table wp_posts ( ID integer primary key auto_increment, post_title varchar(30), post_type varchar(30) );
✓
create table wp_postmeta ( ID integer primary key auto_increment, post_id integer, meta_key varchar(30) not null default '_regular_price', meta_value integer not null );
✓
insert into wp_posts (post_title, post_type) values ('Apple Pie','Product'), ('French Toast','Product'), ('Shepards Pie','Product'), ('Jam Pie','Product'), ('Jam Pie','Product'), ('Plate','Not a Product'), ('Bucket','Not a Product'), ('Chequebook','Not a Product'), ('French Toast','Product'), ('French Toast','Product'), ('Banana','Product'), ('Banana','Product'), ('Banana','Product');
✓
insert into wp_postmeta (post_id, meta_value) values (1,10), (2,5), (3,9), (4,8), (5,11), (6,12), (7,10), (8,6), (9,1), (10,1), (11,7), (12,2), (13,2);
✓
SELECT wp_posts.post_title, MIN(wp_postmeta.meta_value) FROM wp_postmeta JOIN wp_posts ON wp_postmeta.post_id = wp_posts.id WHERE wp_posts.post_type = 'Product' AND wp_postmeta.meta_key = '_regular_price' GROUP BY wp_posts.post_title ORDER BY wp_posts.post_title
post_title | MIN(wp_postmeta.meta_value) :----------- | --------------------------: Apple Pie | 10 Banana | 2 French Toast | 1 Jam Pie | 8 Shepards Pie | 9
db <>提琴here
编辑:我对最初的问题不够清楚和明确-我想折叠重复的post_titles
并使用与wp_postmeta.post_id
对应的MIN(pm.meta_value)
答案 0 :(得分:1)
您不能只将其包含在const a: A = ....;
const b1: B = ....;
const b2: B = ....;
.
.
.
const bn: B = ....;
const c: C = ....;
const arr: MyArrayType = [a, b1, b2,...., bn, c]; //compiles
const arr2: MyArrayType = [c, b1, b2,...., bn, a]; //doesn't compile
中吗?
GROUP BY
SELECT p.post_title, p.id, MIN(pm.meta_value)
FROM wp_postmeta pm JOIN
wp_posts p
ON pm.post_id = p.id
WHERE p.post_type = 'Product' AND pm.meta_key = '_regular_price'
GROUP BY p.post_title, p.id
ORDER BY p.post_title;
与post_id
相同,因此您最好使用它。
编辑:
如果标题可以重复,则只需使用相关的子查询:
p.id
答案 1 :(得分:1)
如果我正确地跟随了您,则可以使用窗口函数解决您的问题:
SELECT x.post_title, x.id
FROM (
SELECT wp_posts.post_title, wp_postmeta.id, ROW_NUMBER() OVER (PARTITION BY wp_posts.post_title ORDER BY wp_postmeta.meta_value) rn
FROM wp_postmeta
INNER JOIN wp_posts ON wp_postmeta.post_id = wp_posts.id
WHERE wp_posts.post_type = 'Product' AND wp_postmeta.meta_key = '_regular_price'
) x WHERE x.rn = 1;
窗口函数是用于此类用例的方式(如果我理解正确的话)。在效率和可读性方面,它们通常优于其他解决方案。
如果RDBMS不支持窗口功能,一种解决方案是使用具有NOT EXISTS条件的相关子查询,以确保对于给定帖子标题,不存在具有较小元值的记录。
SELECT p.post_title, MIN(m.id)
FROM
wp_postmeta m
INNER JOIN wp_posts p
ON p.id = m.post_id
AND p.post_type = 'Product'
WHERE
m.meta_key = '_regular_price'
AND NOT EXISTS (
SELECT 1
FROM
wp_postmeta m1
INNER JOIN wp_posts p1
ON p1.id = m1.post_id
AND p1.post_type = 'Product'
WHERE
m1.meta_key = '_regular_price'
AND p1.post_title = p.post_title
AND m1.meta_value < m.meta_value
)
GROUP BY p.post_title
注意:我对您的SQL做了一些清理(添加了表别名,并将某些条件移到了相关联接的ON子句中。)
答案 2 :(得分:1)
您可以使用CTE托盘:
WITH T1
AS ( SELECT post_title, MIN(id) AS ID
FROM wp_posts
GROUP BY post_title )
SELECT T1.ID, wp_posts.post_title, MIN(wp_postmeta.meta_value)
FROM wp_postmeta
JOIN wp_posts ON wp_postmeta.post_id = wp_posts.id
JOIN T1 ON T1.post_title = wp_posts.post_title
WHERE wp_posts.post_type = 'Product'
AND wp_postmeta.meta_key = '_regular_price'
GROUP BY T1.ID, wp_posts.post_title
ORDER BY wp_posts.post_title;
编辑:
您的表wp_posts应该看起来像这样
Id, post_title, post_type
1, 'Apple Pie','Product'
2, 'French Toast','Product'
3, 'Shepards Pie','Product'
4, 'Jam Pie','Product'
5, 'Plate','Not a Product'
6, 'Bucket','Not a Product'
7, 'Chequebook','Not a Product'
8, 'Banana','Product'
并且比这样的wp_postmeta表数据中的
post_id, meta_value
1, 10
2, 5
3, 9
4, 8
4, 11
5, 12
6, 10
7, 6
2, 1
2, 1
8, 7
8, 2
8, 2
查询如下
SELECT wp_postmeta.post_id, wp_posts.post_title, MIN(wp_postmeta.meta_value)
FROM wp_postmeta
JOIN wp_posts ON wp_postmeta.post_id = wp_posts.id
WHERE wp_posts.post_type = 'Product'
AND wp_postmeta.meta_key = 'REG PRICE'
GROUP BY wp_postmeta.post_id, wp_posts.post_title
ORDER BY wp_posts.post_title;