Question

我正在尝试从我的日志中删除重复的时间戳，从而必须将重复行中的数组值连接到前一个数组行的值中。.

到目前为止，我已经设法删除了重复的时间戳。但是，如果在该特定数组中不存在datestamp，我很难将数组值连接到先前的值中。

请帮助我将值压缩到以前的数组中？

日志文件遵循以下格式：

20160420084726:-
20160420085418:[111783178, 111557953, 111646835, 111413356, 111412662, 105618372, 111413557]
20160420085418:[111413432, 111633904, 111783198, 111792767, 111557948, 111413225, 111413281]
20160420085418:[111413432, 111633904, 111783198, 111792767, 111557948, 111413225, 111413281]
20160420085522:[111344871, 111394583, 111295547, 111379566, 111352520]
20160420090022:[111344871, 111394583, 111295547, 111379566, 111352520]

如何删除重复的时间戳，同时将值保留在前一行中，同时保留最后的压缩值/ n换行符。

<?php
$filename = "datesandids.log";
$lines = explode("\n", file_get_contents($filename));
print_r($lines);

$count = count($lines);
for ($i = 0;$i < $count;$i++) {
    $lineattr = explode(":", $lines[$i]);
    echo $lines[$i];
}

foreach ($lines as $linevar => $row) {
    $line = explode(":", $linevar);
    print_r($lines);
}

$handle = fopen("$filename", "r");
$datevar = array();
while ($line = fgets($handle)) {
    $line = trim($line);
    $data = explode(":", $line);
    $datevar[] = $data;
}

var_dump($datevar);

$found = array();
function concatArray($array, $keys, $glue = " ") {
    $last = null;
    foreach ($array as $key => & $value) {
        if (in_array($key, $keys)) {
            if ($last === null) {
                $last = $key;
                continue;
            }
            $array[$last] .= $glue . $value;
            unset($array[$key]);
        }
    }
    return $array;
}

foreach ($datevar as $i => $x) {
    if (in_array($x[0], $found)) {
        $datevar[$i][0] = '';
        $date = array(
            $datevar
        );
        print_r(concatArray($date, array(
            0,
            1
        )));
    }
    else {
        $found[] = $x[0];
    }
}

print_r($datevar);
foreach ($datevar as $key => $value) {
    $datevar[$key] = preg_replace("/\[/", "", $value);
}

foreach ($datevar as $key => $value) {
    $datevar[$key] = preg_replace("/\]/", "", $value);
}
print_r($datevar);
?>

我正在尝试生成以下数组信息：

Array(
    [0] => Array(
        [0] => 20160420084726
        [1] => -
    )

    [1] => Array(
        [0] => 20160420085418
        [1] => 111783178, 111557953, 111646835, 111413356, 111412662, 105618372, 111413557, 111413432, 111633904, 111783198, 111792767, 111557948, 111413225, 111413281, 111413432, 111633904, 111783198, 111792767, 111557948, 111413225, 111413281
    )

    [2] => Array(
        [0] => 20160420085522
        [1] => 111344871, 111394583, 111295547, 111379566, 111352520
    )

    [3] => Array(
        [0] => 20160420090022
        [1] => 111344871, 111394583, 111295547, 111379566, 111352520
    )
)

我实际上正在得到：

Array(
    [0] => Array(
        [0] => 20160420084726
        [1] => -
    )

    [1] => Array(
        [0] => 20160420085418
        [1] => 111783178, 111557953, 111646835, 111413356, 111412662, 105618372, 111413557
    )

    [2] => Array(
        [0] => 
        [1] => 111413432, 111633904, 111783198, 111792767, 111557948, 111413225, 111413281
    )

    [3] => Array(
        [0] => 
        [1] => 111413432, 111633904, 111783198, 111792767, 111557948, 111413225, 111413281
    )

    [4] => Array(
        [0] => 20160420085522
        [1] => 111344871, 111394583, 111295547, 111379566, 111352520
    )

    [5] => Array(
        [0] => 20160420090022
        [1] => 111344871, 111394583, 111295547, 111379566, 111352520
    )
)

Answer 1

您可以尝试这样的方法：

<?php
$filename = "datesandids.log";
$rows = explode(PHP_EOL, file_get_contents($filename));
$result = Array();

foreach($rows as $key => $row){
    $keyval = explode(':', $row);

    $keyval[1] = str_replace('[', '', $keyval[1]);
    $keyval[1] = str_replace(']', '', $keyval[1]);
    $keyval[1] = explode(', ', trim($keyval[1]));

    if(!isset($result[$keyval[0]])){
        $result[$keyval[0]] = $keyval[1];
    }else{
        $result[$keyval[0]] = array_merge($result[$keyval[0]], $keyval[1]);
    }
}

var_dump($result);

has_term()说：

PHP中的数组实际上是有序映射。地图是一种将值与键关联。此类型针对以下几种进行了优化不同用途；可以将其视为数组，列表（向量），哈希表格（地图的实现），字典，集合，堆栈，排队，甚至更多。由于数组值可以是其他数组，所以树多维数组也是可能的。

通过这种方式，您不必担心重复太多

此外，我建议您使用PHP documentation爆炸文件，这样您就不会在其他系统上遇到麻烦了

输出将是这样的：

array(4){ 
    [20160420084726]=> array(1) { 
        [0]=> string(1) "-" 
    } 

    [20160420085418]=> array(21) { 
        [0]=> string(9) "111783178" 
        .
        .
        [20]=> string(9) "111413281" 
    } 

    [20160420085522]=> array(5) { 
        [0]=> string(9) "111344871" 
        .
        .
        [4]=> string(9) "111352520" 
    } 

    [20160420090022]=> array(5) { 
        [0]=> string(9) "111344871"
        .
        .
        [4]=> string(9) "111352520" 
    } 
}

将数组键与上一个数组元素连接

1 个答案: