变量或类型和成本:
pasta_types = "Lasagne, Spaghetti, Macaroni, Cannelloni, Ravioli, Penne, Tortellini, Linguine, Farfalle, Fusilli"
pasta_costs = "6.00, 4.00, 3.15, 8.50, 9.00, 3.15, 5.00, 4.00, 4.25, 4.75"
查看输入内容是否具有可变类型的面食的函数:
def inventory(pt):
return(pt.title() in pasta_types)
输入:
type = input('What pasta would you like: Lasagne, Spaghetti, Macaroni, Cannelloni, Ravioli, Penne, Tortellini, Linguine, Farfalle, and Fusilli ')
调用函数:
have = inventory(type)
如何找出选择了多少个参数?
答案 0 :(得分:0)
这是一个类似的示例,该示例构建并使用字典将每种面食类型的名称与其成本相关联:
pasta_types = "Lasagne, Spaghetti, Macaroni, Cannelloni, Ravioli, Penne, Tortellini, " \
"Linguine, Farfalle, Fusilli"
pasta_costs = "6.00, 4.00, 3.15, 8.50, 9.00, 3.15, 5.00, 4.00, 4.25, 4.75"
# Create a dictionary associating (lowercase) pasta name to its (float) cost.
inventory = dict(zip(pasta_types.lower().replace(' ', '').split(','),
map(float, pasta_costs.replace(' ', '').split(','))))
## Display contents of dictionary created.
#from pprint import pprint
#print('inventory dictionary:')
#pprint(inventory)
while True:
pasta_type = input('What pasta would you like: ' + pasta_types + '?: ')
if pasta_type.lower() in inventory:
break # Got a valid response.
else:
print('Sorry, no {!r} in inventory, please try again\n'.format(pasta_type))
continue # Restart loop.
print('{} costs {:.2f}'.format(pasta_type, inventory[pasta_type]))