在列表视图中按位置编辑项目

时间:2019-02-06 16:13:16

标签: android android-listview

嗨,我是一名新的android开发人员。点击后,我尝试更改项目中的某些元素,这是我的代码

ListView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) {
                ImageView img = findViewById(R.id.imageView2);
                img.setImageResource(R.drawable.validate);
                TextView txtNumTicket, txtCaisse;
                txtNumTicket = findViewById(R.id.ref);
                txtCaisse = findViewById(R.id.textView);
                txtNumTicket.setTextColor(ContextCompat.getColor(Commande.this, R.color.bon));
                txtCaisse.setTextColor(ContextCompat.getColor(Commande.this, R.color.bon));
                Toast.makeText(getApplicationContext(), "You have selected item no."
                        + (i + 1) + "", Toast.LENGTH_SHORT).show();

            }
        });

当位置等于6时,我想返回初始状态(将图像更改为R.id.novalidate和彩色textview),该怎么办?

1 个答案:

答案 0 :(得分:0)

评论后更新:

if (yourListView.getAdapter().getCount()  == 6) {
    img.setImageResource(R.drawable.novalidate);
    txtNumTicket.setTextColor(ContextCompat.getColor(Commande.this, R.color.your_new_colour));
    txtCaisse.setTextColor(ContextCompat.getColor(Commande.this, R.color.your_new_colour));
}

第二次更新: 根据{{​​3}},您可以按照以下方法在列表的特定位置获取视图

public View getViewByPosition(int pos, ListView listView) {
    final int firstListItemPosition = listView.getFirstVisiblePosition();
    final int lastListItemPosition = firstListItemPosition + listView.getChildCount() - 1;

    if (pos < firstListItemPosition || pos > lastListItemPosition ) {
        return listView.getAdapter().getView(pos, null, listView);
    } else {
        final int childIndex = pos - firstListItemPosition;
        return listView.getChildAt(childIndex);
    }
}

因此,您可以通过调用以下内容获得所需的视图:

View view = getViewByPosition (number_of_the_view_you_want_to_change, name_of_your_listview);

然后绑定该项目的文本视图/图像视图(view.findViewById(...))并如上所述设置颜色和文本