SQL WHEN函数-如何修复语法错误？

Question

我是SQL编码的新手，到目前为止，我仅遇到一个错误代码。 在第二行WHEN CONVERT：

（{rd.254是我的餐桌日期栏）

CASE WHEN CONVERT(date,rd.F254) Between 
CONVERT(date,getdate()-7) AND CONVERT(date, getdate()-1) THEN rd.F64 END AS QtyLastWeek

WHEN CONVERT(date,rd.F254) <= CONVERT(date,getdate()-8) THEN rd.F64 END AS Qty2WeeksAgo

我正在尝试查找并修复语法。

Answer 1

语法错误。如果要选择2列QtyLastWeek和Qty2WeeksAgo，则必须在QtyLastWeek之后使用逗号，并使用另一个CASE表达式。

SELECT 
    CASE WHEN CONVERT(date,rd.F254) BETWEEN CONVERT(date,getdate()-7) AND CONVERT(date, getdate()-1) THEN rd.F64 END AS QtyLastWeek,
    CASE WHEN CONVERT(date,rd.F254) <= CONVERT(date,getdate()-8) THEN rd.F64 END AS Qty2WeeksAgo

Answer 2

您缺少逗号和大小写

CASE WHEN CONVERT(date,rd.F254) Between CONVERT(date,getdate()-7) AND CONVERT(date, getdate()-1) THEN 
   rd.F64 
END AS QtyLastWeek,
CASE WHEN CONVERT(date,rd.F254) <= CONVERT(date,getdate()-8) THEN 
   rd.F64 
END AS Qty2WeeksAgo

Answer 3

您在第二个case语句中缺少case关键字。尝试这个 ！

CASE WHEN CONVERT(date,rd.F254) Between CONVERT(date,getdate()-7) AND CONVERT(date,getdate()-1) 
THEN rd.F64 
END AS QtyLastWeek,
CASE   WHEN CONVERT(date,rd.F254) <= CONVERT(date,getdate()-8) 
      THEN rd.F64 
END AS Qty2WeeksAgo