假设
search()比较public function search($params)
{
$query = Report::find();
$dataProvider = new ActiveDataProvider([
'query' => $query,
'sort' => [
'defaultOrder' => [
'created' => SORT_DESC,
]
],
'pagination' => [
'pageSize' => 100,
],
]);
$this->load($params);
if (!$this->validate()) {
return $dataProvider;
}
$query->andFilterWhere([
'id' => $this->id,
'created' => $this->created,
'updated' => $this->updated,
'closed' => $this->closed,
'user_id' => $this->user_id,
'status_id' => $this->status_id,
'location_id' => $this->location_id,
'typeperson_id' => $this->typeperson_id,
'field_cpfcnpj' => $this->field_cpfcnpj,
]);
if ($this->start_date !== null && $this->end_date !== null) {
$query->andFilterWhere(
[
'BETWEEN',
new Expression(
'DATE_FORMAT(created_at,"%Y/%m/%d")'
),
date("Y/m/d", strtotime($this->start_date)),
date("Y/m/d", strtotime($this->end_date)),
]
);
}
$query->andFilterWhere(['between', 'closed', $this->start_closed, $this->end_closed]);
return $dataProvider;
}
和Currency::where('id', '>', 0)->update(['default' => 0]);
并打印List1 = [ 23, 45, 6, 7, 34]
List2 = [46, 23, 1, 14, 68, 56]
中在List1中具有双值的元素
List2答案 0 :(得分：8)
尝试一下：
Output = [i for i in List1 if i*2 in List2]
答案 1 :(得分：3)
您可以将list2转换为一个集合以进行有效的查找，并使用具有上述条件的列表理解来获得所需的输出：
set2 = set(List2)
[i for i in List1 if i * 2 in set2]
答案 2 :(得分：1)
您已经有了答案，但是只是为了简单起见。基本上，您想遍历List1并检查List2中是否包含double值。如果是这样，请将元素添加到output数组中。
List1 = [ 23, 45, 6, 7, 34]
List2 = [46, 23, 1, 7, 14, 68, 56]
output = []
for i in List1:
if i*2 in List2:
output.append(i)
print output
答案 3 :(得分：1)
您已经得到答案。但是，仅出于娱乐目的，我想出了以下方法。我没有对这里列出的所有方法进行基准测试。这样做很有趣。这是一个有趣的问题，可以进一步研究。但是，仅出于此目的，我介绍了我所做的解决方案。
import numpy as np
l = np.array(List1) * 2
print(l)
## array([46, 90, 12, 14, 68])
print(set(l) & set(List2))
## {68, 46, 14}
l2 = set(l) & set(List2)
print([List1[list(np.nonzero(l == i))[0][0]] for i in l if i in l2])
## [23, 7, 34]
它使用numpy的广播以及Python set的快速交集操作。如果两个列表很大，这可能很有用。