Question

我目前正在研究Laravel。我的MongoDB中有两个集合，集合'users'具有用户详细信息，集合'user_details'具有与其他活动相关的其他一些用户详细信息。这两个集合都有一个共同的字段“ user_id”。我想进行汇总查询，以便可以通过单个查询获取结果。

最初，我要查询50个用户，然后循环访问用户集合中的“ user_id”字段，以从“ user_details”集合中获取用户详细信息（如果有）。由于某些原因，它不适用于某些用户。

//intially i was trying this
function get_mongo_user_details($skip,$limit){
       $users =  DB::connection('mongodb')->collection('users')- 
          >skip($skip)->take($limit)->get()->toArray();
        $count = 0;
    foreach ($users as $user) {
    $subs = DB::connection('mongodb')- 
                    >collection('user_details')- 
                    >where('user_id',$user['user_id'])->get()- 
                    >toArray();
    if (!empty($subs)) {
        $users[$count]['details'] = $subs;
    }
    $count++;
    }
return $users;
}

//later I tried an aggregate query
$users = DB::connection('mongodb')->collection('users')->raw()- 
   >aggregate([
            [
               '$lookup' =>
                 [
                   'from' => 'user_details',
                   'localField' => 'user_id',
                   'foreignField'=> 'user_id',
                   'as'=> 'details'
                 ]
            ]
        ])->skip($skip)->take($limit)->get()->toArray();
//I actually don't have that much of knowledge about mongoDB aggregate query. I read mongoDB docs but wasn't that helpful for me.

预期结果是来自“用户”集合的数组，其键为“细节”和“ user_details”集合值。但是我收到错误或带有空白集合值的MongoDB对象。

MongoDB在Laravel中使用接受和跳过条件聚合查询

0 个答案: