Question

我对SQL方面还很陌生。我一直在尝试向您介绍条件，但是让它确定查询是否等于1个结果或多个结果。我的物品在下面。

我可能做错了所有，但以为我会问。

 SELECT employee_name
      , transaction_id
      , department
      , transaction_date
      , transaction_day
   FROM employee_transactions
  WHERE transaction_date 
BETWEEN '2018-08-20 07:14:35.000' 
    AND '2019-02-05 08:29:56.000'
    AND CASE WHEN '$variable' = 'All' 
             THEN inc_day IN (
                 SELECT DISTINCT transaction_day 
                   FROM employee_transactions
           ) ELSE inc_day in ('$variable')
             END

在列交易日中，我的意思是星期一，星期二，星期三等条目存在，但都不在那里。因此，在表单上，如果他们选择了全天所有的数据，而不只是一个，但是如果他们选择了周一的数据，则只显示monda

Answer 1

您应该像下面这样编写查询。

SELECT employee_name, 
        transaction_id, 
        department, 
        transaction_date, 
        transaction_day

  FROM employee_transactions
  WHERE transaction_date 
  BETWEEN '2018-08-20 07:14:35.000' 
  AND '2019-02-05 08:29:56.000'
  AND ( '$variable' = 'All' OR inc_day = '$variable')

当$ variable ='ALL'时，上述查询将返回所有记录，否则仅匹配记录。

假设“ $ variable”将在执行查询之前被替换。

Answer 2

您可以尝试这样

if($variable == "All")
{ 
   $query = "SELECT employee_name, transaction_id , department , transaction_date , 
   transaction_day
   WHERE transaction_date BETWEEN '2018-08-20 07:14:35.000' AND '2019-02-05 08:29:56.000'
   GROUP BY transaction_date"
}
else
{
   $query = "SELECT employee_name, transaction_id , department , transaction_date , transaction_day
   FROM employee_transactions
   WHERE transaction_date BETWEEN '2018-08-20 07:14:35.000'  AND '2019-02-05 08:29:56.000'
   AND inc_day in ($variable)"
}

SQL灵活查询结果

2 个答案: