Question

ShieldUI v 1.7.36 NP

URL：http://hccm.org/gala_signup_list.php

代码

HTML：

<div class="about-bottom">
    <div class="col-md-12 about-left">
        <div id="grid"></div>
    </div>
</div>

Javascript：

$(document).ready(function() {
    $('#return_btn').click(function() {
        window.location = 'gala.php';
    })
    plgrid = $("#grid").shieldGrid({
    dataSource: {
        remote: {
            read: {
                url: "api/GetGalaSignupList",
                dataType: "json",
                xhrFields: {
                    withCredentials: false
                }
            }
        },
        noRecordsText: "There are no Registrants",
        columns: [
            {field:'registrant_name', title: "Registrant Name", width: "30%"},
            {field: 'registrant_email', title: "Email", width: "30%"},
            {field: 'registrant_phone', title: "Phone"},
            {field: 'registrant_mail', title: "Address", width: "30%"},
            {field: 'table_name', title: "Table Name", width: "20%"},
            {field: 'numtix', title: "Num Tix", width: "20%"}
        ]
        }
    });
    plgrid.show();
});

数据，可以在URL上看到<snip>数据

[
   {
      "registrant_name":"Jeff Seiler",
      "registrant_email":"<snip>",
      "registrant_phone":"<snip>",
      "registrant_mail":"507 Las Colinas",
      "ticket_type":"Individual",
      "table_name":"Mr and Mrs Jeff Seiler",
      "numtix":"2"
   },
   {
      "registrant_name":"Jan Halstead",
      "registrant_email":"<snip>",
      "registrant_phone":"<snip>",
      "registrant_mail":"115 Mason Oaks",
      "ticket_type":"Individual",
      "table_name":"",
      "numtix":"1"
   }
]

但是它没有显示基于title属性的标题，它仅显示JSON列名称。我做错了什么导致这个？我可以更改JSON，但想知道为什么title属性不起作用。

Answer 1

我看到您正在从url远程读取数据，我认为您应该定义一个数据源中使用的字段的模式。您可以在这里查看它们的状态定义。您应该指出路径和数据类型。

https://www.shieldui.com/documentation/datasource/javascript/api/settings/schema/fields

我怀疑未显示标题的原因是您尚未定义字段架构。

列标题未按设计显示

1 个答案: