如果条件相同，则选择if元素，如果有更多同级元素

Question

如果有更多具有相同类的兄弟元素，我想选择具有相同文本的元素$（'。art-h .head-art'）

if($('.art-h .head-art').text() == $(this).text()) { ... }

Answer 1

这里是使用香草JS和find()方法的示例。

这对您有用吗？

const getArt = (text) => {
  return Array.from(document.querySelectorAll('.head-art')).find(e => e.innerText === text);
};

console.log(getArt('some text'));

console.log(getArt('anoter text'));

<div class="art-h">
  <div class="head-art">some text</div>
</div>
<div class="art-h">
  <div class="head-art">anoter text</div>
</div>
<div class "related-heads">
  <h1 class="rel-head">some text</h1>
</div>

Answer 2

我相信您需要使用.filter ..试试下一个代码

$('.rel-head').click(function() {
  var el = $(this);
  $('.art-h .head-art').filter(function(){
      return $(this).text().trim() == el.text().trim();
  }).toggle();  // change toggle() with any action you want
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="art-h">
  <div class="head-art">some text</div>
</div>
<div class="art-h">
  <div class="head-art">another text</div>
</div>
<div class="related-heads">
  <h1 class="rel-head">some text</h1>
</div>
<div class="related-heads">
  <h1 class="rel-head">another text</h1>
</div>