我正在将格式化的文本写到Oracle表中的CLOB
上。最终,在进程运行时,表将被锁定。当我们的DBA签出连接时,似乎我已经在表上创建了多个锁,而其他用户没有其他连接。为什么下面的代码最终会在表上创建锁?在创建锁之前,此代码通常每天需要花费几天时间运行几次,每次运行100次。似乎没有挂起的交易。
public void Update_Html_Out(string key, string shortTitle, string htmlText)
{
byte[] newvalue = Encoding.Unicode.GetBytes(htmlText);
string sql = "UPDATE html_out SET short_title = :short_title, actual_text = :clob WHERE key = :key";
using (var conn = new OracleConnection(_connectionString))
using (var cmd = new OracleCommand(sql, conn))
{
conn.Open();
using (var transaction = conn.BeginTransaction(IsolationLevel.ReadCommitted))
{
cmd.Transaction = transaction;
using (var clob = new OracleClob(conn))
{
clob.Write(newvalue, 0, newvalue.Length);
cmd.Parameters.Add("short_title", shortTitle);
cmd.Parameters.Add("clob", clob);
cmd.Parameters.Add("key", key);
cmd.ExecuteNonQuery();
transaction.Commit();
}
}
}
}
答案 0 :(得分:0)
尝试此代码。请注意,您需要保存CLOB,而不是BLOB(如您所说)
public void Update_Html_Out(string key, string shortTitle, string htmlText)
{
string sql = @"UPDATE html_out SET
short_title = :short_title,
actual_text = :clob
WHERE key = :key";
using (var conn = new OracleConnection(_connectionString))
{
conn.Open();
using (var transaction = conn.BeginTransaction(IsolationLevel.ReadCommitted))
{
using (var cmd = new OracleCommand(sql, conn))
{
cmd.Transaction = transaction;
cmd.Parameters.Add("short_title", OracleDbType.Varchar2, shortTitle, ParameterDirection.Input);
cmd.Parameters.Add("clob", OracleDbType.Clob, htmlText, ParameterDirection.Input);
cmd.Parameters.Add("key", OracleDbType.Varchar2, key, ParameterDirection.Input);
cmd.ExecuteNonQuery();
}
transaction.Commit();
}
}
}