我有2张这样的桌子:
table_a
id col2
1 A
1 B
2 A
2 B
3 B
table_b
id col1
1 X
2 Y
3 Z
结果:
id col1 col2
1 X A_B
2 Y A_B
3 Z B
我该如何实现?
答案 0 :(得分:3)
您要listagg()
:
select b.id, b.col1,
listagg(a.col2, '_') within group (order by a.col2) as col2
from table_b b join
table_a a
on b.id = a.id
group by b.id, b.col1;