Question

我想捕获组1中的所有者或生成器，否则在组2中遇到直到连字符和/或空格后跟数字的所有文本，然后从以下文本直到组3中行尾的任何数字： -

PRD Hervey Bay 07 2525 1919
RG Sprake &amp; Co Maryborough 4141 2424
Owner Robert - 0429 966 391
Owner Maureen - 07 8888 4444 - 0422000 111
Owner Wayne - 0430 555 666
Builder Scott - 0444 555 777

我当前正在使用的表达式：-

/(Owner|Builder)([^-]+)-|\s+(\d.*)/gm

第2组中的“ PRD Hervey Bay”和“ RG Sprake＆Co Maryborough”不匹配。

任何帮助表示赞赏！

特伦特。

Answer 1

您可以使用此正则表达式获取所需的结果：

/^(Owner |Builder )?(.*?)(?=-| \d)[- ]+(.*)$/m

它查找（可选）字符串Owner或Builder；后跟一些最少的字符，直到-或空格后跟一个数字；后跟一定数量的-或空格，然后是字符，直到行尾。要在PHP中使用：

$text = <<<EOD
PRD Hervey Bay 07 2525 1919
RG Sprake &amp; Co Maryborough 4141 2424
Owner Robert - 0429 966 391
Owner Maureen - 07 8888 4444 - 0422000 111
Owner Wayne - 0430 555 666
Builder Scott - 0444 555 777
EOD;
preg_match_all('/^(Owner |Builder )?(.*?)(?=-| \d)[- ]+(.*)$/m', $text, $matches);
print_r($matches);

输出：

Array ( 
  [0] => Array (
    [0] => PRD Hervey Bay 07 2525 1919
    [1] => RG Sprake &amp; Co Maryborough 4141 2424
    [2] => Owner Robert - 0429 966 391
    [3] => Owner Maureen - 07 8888 4444 - 0422000 111
    [4] => Owner Wayne - 0430 555 666
    [5] => Builder Scott - 0444 555 777 
    )
  [1] => Array (
    [0] => 
    [1] =>
    [2] => Owner
    [3] => Owner
    [4] => Owner
    [5] => Builder
    )
  [2] => Array (
    [0] => PRD Hervey Bay
    [1] => RG Sprake &amp; Co Maryborough
    [2] => Robert
    [3] => Maureen
    [4] => Wayne
    [5] => Scott
    )
  [3] => Array (
    [0] => 07 2525 1919
    [1] => 4141 2424
    [2] => 0429 966 391
    [3] => 07 8888 4444 - 0422000 111
    [4] => 0430 555 666
    [5] => 0444 555 777
    )
  )

Demo on 3v4l.org

请注意，这确实在最后一组中保留了一些空格和-，您可以使用array_walk轻松删除它们（如果需要）：

array_walk($matches[3], function (&$v) { $v = preg_replace('/[^\d]/', '', $v); });

Demo on 3v4l.org

正则表达式捕获组2捕获与捕获组1不匹配的内容

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