Question

下面的列表包含id的

List id_wanted = ['3894586', '2786438236', '895673985']

鉴于上面的列表，如何从下面的JSON中删除与列表上方的ID相匹配的元素？

JSON：

{
    "animals": [
        {
            "name": "lion",
            "countries": [
                {
                    "name": "kenya",
                    "facts": [
                        {
                            "features": [
                                "young male"
                            ],
                            "age": "2y",
                            "id": "2837492"
                        }
                    ]
                },
                {
                    "name": "tanzania",
                    "facts": [
                        {
                            "features": [
                                "cub"
                            ],
                            "age": "0y",
                            "id": "3894586"
                        }
                    ]
                },
                {
                    "name": "south africa",
                    "facts": [
                        {
                            "features": [
                                "adult lioness"
                            ],
                            "age": "10y",
                            "id": "495684576"
                        },
                        {
                            "features": [
                                "young female"
                            ],
                            "age": "4y",
                            "id": "2786438236"
                        }
                    ]
                }
            ]
        },
        {
            "name": "giraffe",
            "countries": [
                {
                    "name": "zambia",
                    "facts": [
                        {
                            "features": [
                                "ex captivity"
                            ],
                            "age": "20y",
                            "id": "343453509"
                        }
                    ]
                },
                {
                    "name": "kenya",
                    "facts": [
                        {
                            "features": [
                                "male"
                            ],
                            "age": "17y",
                            "id": "85604586"
                        }
                    ]
                },
                {
                    "name": "uganda",
                    "facts": [
                        {
                            "features": [
                                "young female"
                            ],
                            "age": "4y",
                            "id": "895673985"
                        },
                        {
                            "features": [
                                "none"
                            ],
                            "age": "11y",
                            "id": "39860394758936764"
                        }
                    ]
                }
            ]
        }
    ]
}

例如，由于id与列表id_wanted匹配，因此将从上面的JSON中删除以下块

                    {
                        "features": [
                            "young female"
                        ],
                        "age": "4y",
                        "id": "2786438236"
                    }

Answer 1

假设您的json是变量inputJson中的字符串，那么从原始文件中过滤掉那些值来构建新的Json文档可能会更容易：

import groovy.json.*

def json = new JsonSlurper().parseText(inputJson)

List id_wanted = ['3894586', '2786438236', '895673985']

def result = new JsonBuilder([
    animals: json.animals.collect {[
        name: "$it.name",
        countries: it.countries.collect { [
            name: "$it.name",
            facts: it.facts.findAll { !(it.id in id_wanted) }
        ]}
    ]}
]).toString()

Answer 2

您可以解析// // Call classifier on data // let pyStcriptPath = "\(Bundle.main.bundlePath)/Classification/****Classify.py" // // The fonction I'm calling here, 'shell', is the one defined just above in my question // let pyResult = shell("python", pyStcriptPath, "\(featureVector)", "\(signalType)") json并使用方便的original扩展运算符就地修改结果数据结构：

*.

输出（已删除def json = slurper.parseText(original) json.animals*.countries*.facts*.each { facts -> facts.removeAll { fact -> fact.id in id_wanted } } def filtered = new JsonBuilder(json).toPrettyString() println(filtered)中的事实）：

id_wanted

Groovy从地图上删除

2 个答案: