我有一个以下程序,该程序从csv文件中读取一些数据,但它似乎拒绝所有尝试将“标记”数据读取为整数或以后再将其转换为整数的尝试。我将这个程序基于另一个我具有的功能,它具有完整的功能,唯一的真正区别是整数字段是我正在运行的程序中的浮点数。
我尝试在“ for counter ...”行之后将以下行输入到findHighest函数中。
**Students[0].marks = int(Students[0].marks)**
该代码运行,但未在数据中找到最高编号(最高编号为100时返回96,第二最高编号为96)。我还尝试过更改以下行...
Students[counter].marks = row[3]
并将其更改为...
**Students[counter].marks = int(row[3])**
这给了我以下错误:
ValueError:以10为底的int()无效文字:
我在这里想念什么? :-/
导入csv
class Student:
def __init__(self,forename,surname,form,marks):
self.forename = ""
self.surname = ""
self.form = ""
self.marks = 0
def readFile():
Students = []
filename = "pupils.csv"
csv_file = open(filename, "r")
reader = csv.reader(csv_file)
counter = 0
for row in reader:
Students.append(Student("", "", "", 0))
Students[counter].forename = row[0]
Students[counter].surname = row[1]
Students[counter].form = row[2]
Students[counter].marks = row[3]
counter = counter + 1
return Students
def findHighest(Students):
position=0
highest = Students[0].marks
for counter in range(len(Students)):
Students[counter].marks = int(Students[counter].marks)
if Students[counter].marks > highest:
highest = Students[counter].marks
position = counter
return highest
def displayHighest(highest):
print("the highest pupil score was:", highest)
Students = readFile()
highest = findHighest(Students)
displayHighest(highest)
CSV文件:
答案 0 :(得分:1)
我猜你有多个问题
def findHighest(Students):
position=0
#highest is set to a string. You should set highest to 0
highest = Students[0].marks
for counter in range(len(Students)):
#why do you always set Students[0] and not Students[counter]. You always convert Students[0] to int.
Students[0].marks = int(Students[0].marks)
#As a result you always tests string again strings:
if Students[counter].marks > highest:
highest = Students[counter].marks
position = counter
return highest
这次尝试
Students[counter].marks = int(row[3])
应该是正确的,但ValueError可能表明您的CSV内容并非完全是正确的整数值。请检查您的CSV或处理如下异常: Converting String to Int using try/except in Python
答案 1 :(得分:0)
似乎这是CSV文件而不是代码的问题。我从头开始创建了一个新文件,它的Student [counter] .marks = int(row [3])行工作正常。