我有一张表格,其中包含有关城市之间航班的信息,如下所示:
origin_city dest_city time
Dothan AL Atlanta GA 171
Dothan AL Atlanta GA 171
Dothan AL Elsewhere AL 2
Dothan AL Elsewhere AL 2
Dothan AL Elsewhere AL 2
Boston MA New York NY 5
Boston MA City MA 1
New York NY Boston MA 5
New York NY Boston MA 5
New York NY Boston MA 5
New York NY Poughkipsie NY 2
我想为每个始发城市找到少于3小时的航班百分比。结果是这样的:
Dothan AL 60
Boston MA 50
New York NY 25
我认为可行的代码如下:
SELECT F.origin_city as origin_city,
((SELECT COUNT(*) FROM Flights as F2
WHERE F2.actual_time < 3) / (SELECT COUNT(*) FROM Flights as F3)) * 100
AS percentage
FROM Flights as F
GROUP BY F.origin_city
ORDER BY percentage;
GO
运行它时,如预期的那样,我得到了一个原始城市的列表和一个列,但该百分比始终为0。对于子查询,我还是很困惑(如您所见)。
答案 0 :(得分:1)
我可以使用AVG()
作为窗口函数来做到这一点:
SELECT F.origin_city as origin_city,
AVG( CASE WHEN F2.actual_time < 3 THEN 100.0 ELSE 0 END) as percentage
FROM Flights F
GROUP BY F.origin_city
ORDER BY percentage;
这假设时间以小时为单位。根据Google Maps,您可以在68小时内从多森步行到亚特兰大,因此171可疑。
答案 1 :(得分:0)
您的百分比在整个表格中,而不是按来源城市分组。尝试这样的事情:
SELECT F.origin_city as origin_city,
(SUM(CASE WHEN F.actual_time < 3 THEN 1 ELSE 0 END) / COUNT(*) ) * 100 AS percentage
FROM Flights as F
GROUP BY F.origin_city
ORDER BY percentage;
GO
FWIW当前子查询的问题是当前行与子查询中的数据之间没有联接。您可能将其重写为:
SELECT F.origin_city as origin_city,
((SELECT COUNT(*) FROM Flights as F2
WHERE F2.origin_city = F.origin_city and F2.actual_time < 3) / (SELECT COUNT(*) FROM Flights as F3 where F3.origin_city = F.origin_city)) * 100
AS percentage
FROM Flights as F
GROUP BY F.origin_city
ORDER BY percentage;
GO
但是,当您已经有足够的数据来进行如上所述的计算时,不必为每行重新查询表。