Question

在修改搜索表单中的查询代码之前，我在下面的查询中使用了它，效果很好。

...
$query = Job::where('is_trash', 0);
$query = $query->where('created_at', '>=', Carbon::parse($rFrom)->startOfDay())
        ->where('created_at', '<=', Carbon::parse($rTo)->endOfDay())
        ->where('customer_name', 'like', '%' . $rName . '%')
        ->where('project_name', 'like', '%' . $rProject . '%')
        ->where('job_type', 'like', '%' . $rType . '%');
...

但是现在我将下面的表结构修改为动态显示字段名称通过使用关系查询。

工作表

  +----------------------------------------------------+
     ID | customer_id | job_project_id | job_type_id | ...                                         
  +----------------------------------------------------+
     1  | 1           | 1             | 1       | ...
  +----------------------------------------------------+
     2  | 2           | 7             | 2       | ...
  +----------------------------------------------------+

JobProject表

  +-------------------------------+
     ID | customer_id | name | ...                                         
  +-------------------------------+
     1  | 1           | 1    |...
  +-------------------------------+
     2  | 2           | 7    | ...
  +-------------------------------+

JobType表

  +------------------+
     ID | name  | ...                                         
  +------------------+
     1  | test1 |...
  +------------------+
     2  | test2 | ...
  +------------------+

在Job模型中还包括以下简单关系。这些东西将varchar类型定义为字符串。但是Job模型仅将这些模型的ID定义为job表中的customer_id，project_id和jobType_id。

...

public function user()
{
    return $this->hasOne(User::class);
}

public function customer()
{
    return $this->hasOne(Customer::class);
}

public function jobProject()
{
    return $this->hasOne(JobProject::class);
}

public function jobType()
{
    return $this->hasOne(JobType::class);
}
...

主要问题是，如果搜索输入是customer_name，project_name和job_type，那么如何建立查询关系查询链？因为Job表仅包含这些ID。

Answer 1

<?php 

// Build primitive query
$jobQuery = Job::where('is_trash', 0);

// Use when conditional to check if you need to filter something
$jobQuery->when($from && $to, function($q) use($request) {
        $q->where('created_at', '>=', Carbon::parse($from)->startOfDay())
            ->where('created_at', '<=', Carbon::parse($to)->endOfDay());
    });
// Use whereHas to add a where clause in relations
$jobQuery->when($customerName, function($q) use($request) {
    $q->whereHas('customer', function ($subq) {
        $subq->where('name', 'like', '%' . $customerName . '%');
    });
});


$jobQuery->when($projectName, function($q) use($request) {
    $q->whereHas('jobproject', function ($subq) {
        $subq->where('name', 'like', '%' . $projectName . '%');
    });
});

$jobQuery->when($jobType, function($q) use($request) {
    $q->whereHas('jobtype', function ($subq) {
        $subq->where('name', 'like', '%' . $jobType . '%');
    });
});

Laravel雄辩的模型关系查询

1 个答案: